Question

您好，我正在尝试将town_B的值分配给PHP中的变量。

我尝试使用下面的方法，但没有成功。请提出任何建议。

$varx = $update["result"]["parameters"]["town_two"];

以下是JSON回复

{
  "id": "86726c74-cb52-4f1e-983d-1bc68d8c4f9c",
  "timestamp": "2018-02-22T18:03:12.964Z",
  "lang": "en",
  "result": {
    "source": "agent",
    "resolvedQuery": "Disneyworld CA",
    "action": "sayHello",
    "actionIncomplete": false,
    "parameters": {
      "town_B": [
        "CA"
      ],
      "town_A": "Disneyworld"
    },
    "contexts": [],
    "metadata": {
      "intentId": "65bc2f1f-e127-44de-bd3b-915c8865f472",
      "webhookUsed": "true",
      "webhookForSlotFillingUsed": "false",
      "webhookResponseTime": 1047,
      "intentName": "Geo"
    },
    "fulfillment": {
      "source": "agent",
      "messages": [
        {
          "type": 0,
          "speech": "Please check for correct input"
        }
      ]
    },
    "score": 1
  },
  "status": {
    "code": 200,
    "errorType": "success",
    "webhookTimedOut": false
  },
  "sessionId": "c3de9b17-6cd6-43dc-bf12-6844a6b0930e"
}

Answer 1

我从未见过town_two，可能是town_B

$json = '{
"id": "86726c74-cb52-4f1e-983d-1bc68d8c4f9c",
  "timestamp": "2018-02-22T18:03:12.964Z",
  "lang": "en",
  "result": {
    "source": "agent",
    "resolvedSomething is wrong": "Disneyworld CA",
    "action": "sayHello",
    "actionIncomplete": false,
    "parameters": {
      "town_B": [
        "CA"
      ],
      "town_A": "Disneyworld"
    },
    "contexts": [],
    "metadata": {
      "intentId": "65bc2f1f-e127-44de-bd3b-915c8865f472",
      "webhookUsed": "true",
      "webhookForSlotFillingUsed": "false",
      "webhookResponseTime": 1047,
      "intentName": "Geo"
    },
    "fulfillment": {
      "source": "agent",
      "messages": [
        {
          "type": 0,
          "speech": "Please check for correct input"
        }
      ]
    },
    "score": 1
  },
  "status": {
    "code": 200,
    "errorType": "success",
    "webhookTimedOut": false
  },
  "Something is wrongId": "c3de9b17-6cd6-43dc-bf12-6844a6b0930e"
}';


$update = json_decode($json, true);

echo $update["result"]["parameters"]["town_B"][0];

说明：您需要使用json_decode解码json http://php.net/manual/en/function.json-decode.php

更新：

$update = json_decode($json, true);

echo $update["result"]["parameters"]["town_B"][0];

town_B是一个数组，所以对于输出“CA”，需要选择第一个元素。

获取JSON查询到PHP的值

1 个答案: