如何将值列表迭代为字符串?

时间:2018-02-22 12:22:09

标签: python string python-3.x list iteration

我是Python的新手,请原谅我缺乏理解。

我可以使用BeatifulSoup4下载aapl的数据,将数据分配给特定变量并使用变量创建字典。我想做的是通过网站链接迭代stock列表,并为列表中的不同公司多次运行相同的代码,最后得到每个公司的字典。

import bs4 as bs
import urllib.request


stocks = ['aapl', 'nvda', 'amgn']

sauce = urllib.request.urlopen('https://www.zacks.com/stock/quote/aapl/balance-sheet')
soup = bs.BeautifulSoup(sauce,'lxml')

#Cash & Cash Equivalents
cash_and_equivalents2017 = soup.find_all('td')[33].string
cash_and_equivalents2017 = int(cash_and_equivalents2017.replace(',',''))
cash_and_equivalents2016 = soup.find_all('td')[34].string
cash_and_equivalents2016 = int(cash_and_equivalents2016.replace(',',''))

#Receivables
receivables2017 = soup.find_all('td')[40].string
receivables2017 = int(receivables2017.replace(',',''))
receivables2016 = soup.find_all('td')[41].string
receivables2016 = int(receivables2016.replace(',',''))


aapl = {'Cash & Cash Equivalents':
            {'2017': cash_and_equivalents2017,
             '2016': cash_and_equivalents2016},
        'Receivables':
            {'2017': receivables2017,
             '2016': receivables2016}
        }
print(aapl)

aapl输出以下内容:

{'Cash & Cash Equivalents': {'2017': 74181, '2016': 67155}, 'Receivables': {'2017': 29299, '2016': 30343}}

以上是原始代码,我想用aapl中的sauce替换stocks中的其他字符串值,最终获得多个字典,如下所示,以便我能够只需在stock列表中输入数据,即可自动将各公司的数据下载到3个不同的词典中。

sauce = urllib.request.urlopen('https://www.zacks.com/stock/quote/[stocks]/balance-sheet')

[stocks] = {'Cash & Cash Equivalents':
                {'2017': cash_and_equivalents2017,
                 '2016': cash_and_equivalents2016},
            'Receivables':
                {'2017': receivables2017,
                 '2016': receivables2016}

输出应该是3个字典,名称为aaplnvdaamgn

aapl = {'Cash & Cash Equivalents':
            {'2017': cash_and_equivalents2017,
             '2016': cash_and_equivalents2016},
        'Receivables':
            {'2017': receivables2017,
             '2016': receivables2016}

nvda = {'Cash & Cash Equivalents':
            {'2017': cash_and_equivalents2017,
             '2016': cash_and_equivalents2016},
        'Receivables':
            {'2017': receivables2017,
             '2016': receivables2016}

amgn = {'Cash & Cash Equivalents':
            {'2017': cash_and_equivalents2017,
             '2016': cash_and_equivalents2016},
        'Receivables':
            {'2017': receivables2017,
             '2016': receivables2016}

感谢您的时间和帮助,非常感谢。

2 个答案:

答案 0 :(得分:1)

我不确定我是否正确理解了你的问题。

您是否要为for stock in stocks: # Do your processing here 中的每个条目提出一个请求和处理?

如果是这样,在Python中,您可以使用for循环遍历列表或dict,如下所示:

stocks = {'aapl': {}, 'nvda': {}, 'amgn': {}}
for stock in stocks:

    sauce = urllib.request.urlopen(
        f'https://www.zacks.com/stock/quote/{stock}/balance-sheet')
    soup = bs.BeautifulSoup(sauce, 'lxml')

    # Cash & Cash Equivalents
    cash_and_equivalents2017 = soup.find_all('td')[33].string
    cash_and_equivalents2017 = int(cash_and_equivalents2017.replace(',', ''))
    cash_and_equivalents2016 = soup.find_all('td')[34].string
    cash_and_equivalents2016 = int(cash_and_equivalents2016.replace(',', ''))

    # Receivables
    receivables2017 = soup.find_all('td')[40].string
    receivables2017 = int(receivables2017.replace(',', ''))
    receivables2016 = soup.find_all('td')[41].string
    receivables2016 = int(receivables2016.replace(',', ''))

    stocks[stock] = {'Cash & Cash Equivalents':
                     {'2017': cash_and_equivalents2017,
                      '2016': cash_and_equivalents2016},
                     'Receivables':
                     {'2017': receivables2017,
                         '2016': receivables2016}
                     }

print(stocks)

您可以在以下情况下执行以下操作:

使用dict而不是列表并将已处理的数据存储在其中。

{
    'aapl': 
    {
        'Cash & Cash Equivalents': 
        {
            '2017': 'some value', 
            '2016': 'some value'
        }, 
        'Receivables': 
        {
            '2017': 'some value', 
            '2016': 'some value'
            }
    }, 
    'nvda': 
    {
        'Cash & Cash Equivalents': 
        {
            '2017': 'some value', 
            '2016': 'some value'
        }, 
        'Receivables':
        {
            '2017': 'some value', 
            '2016': 'some value'
        }
    }, 
    'amgn': 
    {
        'Cash & Cash Equivalents': 
        {
            '2017': 'some value', 
            '2016': 'some value'
        }, 
        'Receivables': 
        {
            '2017': 'some value', 
            '2016': 'some value'
        }
    }
}

至于url字符串,我使用了litteral string interpolation method

将输出以下内容:

{{1}}

度过愉快的一天。

答案 1 :(得分:0)

将每个响应附加到这样的一个列表中,然后从dictioanry中添加值:

aapl, nvda, amgn = [{'Cash & Cash Equivalents': {'2017': 74181, '2016': 67155}, 'Receivables': {'2017': 29299, '2016': 30343}},{'Cash & Cash Equivalents': {'2017': 74181, '2016': 67155}, 'Receivables': {'2017': 29299, '2016': 30343}},{'Cash & Cash Equivalents': {'2017': 74181, '2016': 67155}, 'Receivables': {'2017': 29299, '2016': 30343}}]