Question

我有两个问题。

第一个：

SELECT CreatedOn, COUNT(*) AS locationNonProcessed
FROM Table1
WHERE IsActive = 0
GROUP BY CAST(CreatedOn AS DATE), CreatedOn

第二个：

SELECT CreatedOn, COUNT(*) AS locationProcessed
FROM Table1
WHERE IsActive = 1
GROUP BY CAST(CreatedOn AS DATE), CreatedOn

我应该如何对这些查询使用UNION ALL？

Answer 1

我认为你真的不想union all。实现这一点很简单，结果不是很明智（你不会知道哪个是哪个）。

我怀疑你想要条件聚合：

SELECT CAST(CreatedOn AS DATE),
       SUM(CASE WHEN IsActive = 0 THEN 1 ELSE 0 END) AS locationNonProcessed,
       SUM(CASE WHEN IsActive = 1 THEN 1 ELSE 0 END) as locationProcessed
FROM Table1
GROUP BY CAST(CreatedOn AS DATE);

请注意SELECT和GROUP BY。

的修正

如果IsActive仅采用0,1和可能NULL的值，则可以简化为：

SELECT CAST(CreatedOn AS DATE),
       SUM(1 - IsActive) AS locationNonProcessed,
       SUM(IsActive) as locationProcessed
FROM Table1
GROUP BY CAST(CreatedOn AS DATE);

Answer 2

SELECT createdon, IsActive, COUNT(*) AS locationProcessed
FROM Table1
WHERE IsActive in (0, 1)
GROUP BY CAST(CreatedOn AS DATE), CreatedOn, IsActive

GROUP BY CAST(CreatedOn AS DATE), CreatedOn对我来说很奇怪。这与GROUP BY CreatedOn没有什么不同。

Answer 3

SELECT createdon,
       SUM(CASE WHEN IsActive = 0 THEN 1 ELSE 0 END) AS locationNonProcessed,
       SUM(CASE WHEN IsActive = 1 THEN 1 ELSE 0 END) as locationProcessed
FROM Table1
GROUP BY CAST(CreatedOn AS DATE), CreatedOn;

如何使用＆＃34;结合所有＆＃34;在SQL？

3 个答案: