Tomcat9上的Jersey REST服务出现404错误

时间:2018-02-22 11:35:23

标签: java rest tomcat jersey http-status-code-404

所以我尝试使用Jersey 2.25创建一个REST服务,它将在Tomcat 9上运行。我使用gradle作为构建工具。基本上,我关注this vogella tutorial,我做了那里提到的一切。但是,当我尝试通过访问http://localhost:8080/com.krozona.jersey.first/rest/hello在tomcat9上运行它时,我收到404错误。

这是我的web.xml: -

    <?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID" version="3.0">
  <display-name>com.krozona.jersey.first</display-name>
 <servlet>
    <servlet-name>Jersey REST Service</servlet-name>
    <servlet-class>org.glassfish.jersey.servlet.ServletContainer</servlet-class>
     <!-- Register resources and providers under com.vogella.jersey.first package. -->
    <init-param>
        <param-name>jersey.config.server.provider.packages</param-name>
        <param-value>com.krozona.jersey.first</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
  </servlet>
  <servlet-mapping>
    <servlet-name>Jersey REST Service</servlet-name>
    <url-pattern>/rest/*</url-pattern>
  </servlet-mapping>
</web-app>

我的资源类: -

package com.krozona.jersey.first;

import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.Produces;
import javax.ws.rs.core.MediaType;

@Path("/hello")
public class Hello {

  // This method is called if TEXT_PLAIN is request
  @GET
  @Produces(MediaType.TEXT_PLAIN)
  public String sayPlainTextHello() {
    return "Hello Jersey";
  }

  // This method is called if XML is request
  @GET
  @Produces(MediaType.TEXT_XML)
  public String sayXMLHello() {
    return "<?xml version=\"1.0\"?>" + "<hello> Hello Jersey" + "</hello>";
  }

  // This method is called if HTML is request
  @GET
  @Produces(MediaType.TEXT_HTML)
  public String sayHtmlHello() {
    return "<html> " + "<title>" + "Hello Jersey" + "</title>"
        + "<body><h1>" + "Hello Jersey" + "</body></h1>" + "</html> ";
  }

}

最后,我的build.gradle: -

 /*
 * This file was generated by the Gradle 'init' task.
 *
 * This generated file contains a sample Java Library project to get you started.
 * For more details take a look at the Java Libraries chapter in the Gradle
 * user guide available at https://docs.gradle.org/4.5.1/userguide/java_library_plugin.html
 */

plugins {
    // Apply the java-library plugin to add support for Java Library
    id 'java-library'
}

dependencies {
    api 'org.apache.commons:commons-math3:3.6.1'
    implementation 'com.google.guava:guava:23.0'
    testImplementation 'junit:junit:4.12'
    compile 'org.glassfish.jersey.containers:jersey-container-servlet:2.25.1'
}

repositories {
    jcenter()
}

apply plugin: 'war'
apply plugin: 'eclipse-wtp'

project.webAppDirName = 'WebContent'

任何帮助都将非常感激。谢谢!

1 个答案:

答案 0 :(得分:0)

与在Tutorial中提到的一样:

  

此URL源自项目中的上下文根值   属性Web项目设置(默认情况下,这是您的应用程序   名称),并添加了servlet映射URL模式和hello   来自类文件的@Path注释。

因此请确保使用正确的URL:

http://localhost:8080/{your application's name}/rest/hello

端口号也必须正确。