条件下的二进制运算符错误

Question

我想在pickerview行上给出条件，但它只是给我错误。 二进制运算符不能应用于操作数。

let viewList: [String] = ["Fixed", "Recurring"]

func pickerView(_ pickerView: UIPickerView, didSelectRow row: Int, inComponent component: Int) {

    if (viewList[row] == 0) {

    }
}

Answer 1

更新回答

尝试这样做：

class MyViewController: UIViewController {
    fileprivate let viewList: [String] = ["Fixed", "Recurring"]
}

// MARK: - UIPickerViewDelegate
extension MyViewController: UIPickerViewDelegate {
    func pickerView(_ pickerView: UIPickerView, didSelectRow row: Int, inComponent component: Int) {
            print("Selected value \(viewList[row]) at row \(row)")

            if viewList[row] == "Fixed" {
                print("Fixed has been selected!")
            }
    }
}

问题来自您的情况，请尝试下面的代码。

更多信息：Apple Documentation - Collection Types