我有一个关于在R中索引数据帧的问题。这是代码:
Gewicht <- data %>%
group_by(data[[376]]) %>%
summarise(weights = mean(data[[10190]], na.rm = TRUE))
Gewicht2 <- data %>%
group_by(data[[376]]) %>%
summarise(weights = mean(Weights, na.rm = TRUE))
a <- seq(1:10)
b <- rep(c("male", "female"),5)
c <- seq(1:10)
data <- as.data.frame(cbind(a,b,c))
data$c <- as.numeric(data$c)
newdata <- data %>%
group_by(data[[2]]) %>%
summarise(Mean = mean(c, na.rm = TRUE))
newdata2 <- data %>%
group_by(data[[2]]) %>%
summarise(Mean = mean(data[[3]], na.rm = TRUE))
print(newdata)
print(newdata2)
我对两个数据帧都得到了不同的结果。 “newdata”中的所需结果。你能告诉我为什么我得到这两个计算的不同值? 我需要括号用于更复杂的自定义函数,但它似乎写出了整个数据帧的均值,我希望得到每个组的均值。 如何正确使用[]或[[]]?
答案 0 :(得分:0)
a <- c(1,2,3,4,5,6,7,8,9,10)
b <- rep(c("male", "female"),5)
c <- c(1,2,3,4,5,6,7,8,9,10)
data <- data.frame(cbind(a,b,c))
data$c <- as.numeric(as.character(data$c))
c
data$c
print(newdata)
print(newdata2)
newdata <- data %>%
group_by(data[[2]]) %>%
summarise(Mean = mean(c, na.rm = TRUE))
newdata2 <- data %>%
group_by(data[[2]]) %>%
summarise(Mean = mean(data[[3]], na.rm = TRUE))
newdata
newdata2
更新了代码,结果仍然不同:(
答案 1 :(得分:0)
Gewicht&lt; - aggregate(data [[varGewicht]],by = list(data [[varx]]),FUN = mean,na.rm = TRUE)
聚合函数有效: - )