如何在codeigniter中显示特定的分​​页链接

Question

我正在与codeigniter进行交涉，它显示了所有的分页链接

但我只想展示类似1 2 3 Next的内容。  我的代码是

    $start_index = ($this->uri->segment(3)) ? $this->uri->segment(3) : 0;
    $total_reports = $data['losts'];
  $this->load->library('pagination');
    $config['base_url'] = base_url().'Lost/list';
    $config['total_rows'] = count($data['losts']);
    $config['per_page'] = 10; 
    $config['use_page_numbers'] = TRUE;
  $config['num_links'] =  count($data['losts']);
        // Open tag for CURRENT link.
    $config['cur_tag_open'] = '&nbsp;<a class="current">';

    // Close tag for CURRENT link.
    $config['cur_tag_close'] = '</a>';

    // By clicking on performing NEXT pagination.
    $config['next_link'] = 'Next';

    // By clicking on performing PREVIOUS pagination.
    $config['prev_link'] = 'Previous';
    $this->pagination->initialize($config);
    $str_links = $this->pagination->create_links();
    $data["links"] = explode('&nbsp;',$str_links );

提前致谢。

Answer 1

您正在设置$config['num_links']总行数。

但您需要将其设置为要生成的链接数。

$config['num_links'] = 3;

  

您希望之前和之后的“数字”链接数   选择的页码。例如，数字2将放置两位数   在任何一方，如本页顶部的示例链接。

参考：https://www.codeigniter.com/userguide3/libraries/pagination.html#customizing-the-pagination