我有一个XML对象
$xml = SimpleXMLElement Object
(
[a] => SimpleXMLElement Object
(
[b] => SimpleXMLElement Object
(
[c] => 'hey',
),
),
)
现在,我将所有键放在数组中,我想取消设置最后一个键,即来自对象的'c'
$temp = $xml;
$keys_arr = ['a', 'b', 'c'];
foreach($keys_arr => $key){
$temp = $temp->$key;
}
unset($temp) // I want this to work like when we use this 'unset($xml->a->b->c);'
当我们打印$ temp时:
print_r($temp);
输出应为:
SimpleXMLElement Object
(
[a] => SimpleXMLElement Object
(
[b] => SimpleXMLElement Object
(
// without '[c]' key
),
),
)
答案 0 :(得分:0)
这是一种递归方法(与堆叠相反):
代码:(Demo)
function recurse(&$object,$keys){ // modify the input by reference
$key=array_shift($keys);
if(isset($object->$key)){ // avoid trouble
if(empty($keys)){
unset($object->$key); // remove at last key
}else{
recurse($object->$key,$keys); // continue recursion
}
}
}
$xmlstring=<<<XML
<root>
<a>
<b>
<c>hey</c>
</b>
</a>
</root>
XML;
$keys=['a','b','c'];
$xml=new SimpleXMLElement($xmlstring);
echo "Before: \n";
var_export($xml);
echo "\n----\nAfter:\n";
recurse($xml,$keys); // modify input
var_export($xml);
输出:
Before:
SimpleXMLElement::__set_state(array(
'a' =>
SimpleXMLElement::__set_state(array(
'b' =>
SimpleXMLElement::__set_state(array(
'c' => 'hey',
)),
)),
))
----
After:
SimpleXMLElement::__set_state(array(
'a' =>
SimpleXMLElement::__set_state(array(
'b' =>
SimpleXMLElement::__set_state(array(
)),
)),
))
以下是我如何堆叠它以达到相同的结果:Demo
$mod=&$xml; // modify $xml by reference
$keys=['a','b','c'];
$last=array_pop($keys); // assuming the array will not be empty, the array will contain valid/existing object keys
foreach($keys as $key){ // iterate/traverse all remaining keys (e.g. 'a','b' because 'c' was popped off)
$mod=&$mod->$key; // overwrite $mod by reference while traversing
}
unset($mod->$last); // unset the last object
var_export($xml); // print modified $xml to screen
答案 1 :(得分:-1)
走上除最后一项之外的键数组,最后进行取消设置。但是通过引用分配给$ temp !!
$temp = &$xml;
$keys_arr = ['a', 'b', 'c'];
for($i,$size=count($keys_arr); $i<$size-1; $i++){
$temp = &$temp->$keys_arr[$i];
}
unset($temp->$keys_arr[$i]);