Question

我以这样的方式从XSD生成JSON模式： https://dzone.com/articles/generating-json-schema-xsd

一切正常但除了它没有标记XSD标记所需的字段（根据需要标记）（或minOccurs =＆＃34; 1＆＃34;）。杰克逊图书馆可以吗？还是其他一些工具？

我需要这样的东西：

{
"type": "object",
"required": true,
"properties": {
    "field": "value" ...

Answer 1

好的，这是一个答案。您只需在ObjectMapper实例中注册新的JaxbAnnotationModule。这是一段代码：

import com.fasterxml.jackson.databind.AnnotationIntrospector;
import com.fasterxml.jackson.databind.ObjectMapper;
import com.fasterxml.jackson.databind.type.TypeFactory;
import com.fasterxml.jackson.module.jaxb.JaxbAnnotationIntrospector;
import com.fasterxml.jackson.module.jaxb.JaxbAnnotationModule;
import com.fasterxml.jackson.module.jsonSchema.JsonSchema;
import com.fasterxml.jackson.module.jsonSchema.factories.SchemaFactoryWrapper;

    ObjectMapper objectMapper = new ObjectMapper();
    TypeFactory typeFactory = TypeFactory.defaultInstance();
    AnnotationIntrospector introspector = new JaxbAnnotationIntrospector(typeFactory);
    mapper.getDeserializationConfig().with(introspector);
    mapper.getSerializationConfig().with(introspector);

    //To force mapper to include JAXB annotated properties in Json schema
    objectMapper.registerModule(new JaxbAnnotationModule());
    SchemaFactoryWrapper visitor = new SchemaFactoryWrapper();
    objectMapper.acceptJsonFormatVisitor(objectMapper.constructType(YOUR_JAXB_CLASS.class), visitor);

    JsonSchema inputSchema = visitor.finalSchema();
    String schemaString = objectMapper.writerWithDefaultPrettyPrinter().writeValueAsString(inputSchema);

    System.out.println(schemaString);

根据所需xml标记的要求标记json架构字段

1 个答案: