Question

我正在尝试使用python获取热门的YouTube视频数据。虽然我可以成功下载数据，但我无法存储或以csv格式保存。这是我使用的代码：

# -*- coding: utf-8 -*-

import os

import google.oauth2.credentials

import google_auth_oauthlib.flow
from googleapiclient.discovery import build
from googleapiclient.errors import HttpError
from google_auth_oauthlib.flow import InstalledAppFlow


CLIENT_SECRETS_FILE = "client_secret.json"


SCOPES = ['https://www.googleapis.com/auth/youtube.force-ssl']
API_SERVICE_NAME = 'youtube'
API_VERSION = 'v3'

def get_authenticated_service():
  flow = InstalledAppFlow.from_client_secrets_file(CLIENT_SECRETS_FILE, SCOPES)
  credentials = flow.run_console()
  return build(API_SERVICE_NAME, API_VERSION, credentials = credentials)

def print_response(response):
  print(response)


def build_resource(properties):
  resource = {}
  for p in properties:

    prop_array = p.split('.')
    ref = resource
    for pa in range(0, len(prop_array)):
      is_array = False
      key = prop_array[pa]

      # For properties that have array values, convert a name like
      # "snippet.tags[]" to snippet.tags, and set a flag to handle
      # the value as an array.
      if key[-2:] == '[]':
        key = key[0:len(key)-2:]
        is_array = True

      if pa == (len(prop_array) - 1):
        # Leave properties without values out of inserted resource.
        if properties[p]:
          if is_array:
            ref[key] = properties[p].split(',')
          else:
            ref[key] = properties[p]
      elif key not in ref:
        # For example, the property is "snippet.title", but the resource does
        # not yet have a "snippet" object. Create the snippet object here.
        # Setting "ref = ref[key]" means that in the next time through the
        # "for pa in range ..." loop, we will be setting a property in the
        # resource's "snippet" object.
        ref[key] = {}
        ref = ref[key]
      else:
        # For example, the property is "snippet.description", and the resource
        # already has a "snippet" object.
        ref = ref[key]
  return resource

# Remove keyword arguments that are not set
def remove_empty_kwargs(**kwargs):
  good_kwargs = {}
  if kwargs is not None:
    for key, value in kwargs.iteritems():
      if value:
        good_kwargs[key] = value
  return good_kwargs

def videos_list_most_popular(client, **kwargs):
  # See full sample for function
  kwargs = remove_empty_kwargs(**kwargs)

  response = client.videos().list(
    **kwargs
  ).execute()

  return print_response(response)


if __name__ == '__main__':
  # When running locally, disable OAuthlib's HTTPs verification. When
  # running in production *do not* leave this option enabled.
  os.environ['OAUTHLIB_INSECURE_TRANSPORT'] = '1'
  client = get_authenticated_service()

  videos_list_most_popular(client,
    part='snippet,contentDetails,statistics',
    chart='mostPopular',
    regionCode='US',
    videoCategoryId='')

如何以csv格式保存结果？我尝试了以下代码，但收到了错误：

Data = json.loads（str（响应，＆＃39; utf-8＆＃39;））

NameError：name＆＃39; response＆＃39;未定义

Answer 1

NameError意味着变量response不在您运行它的上下文中。我不知道您在代码中放置该行的位置，但是您调用videos_list_most_popular函数，该函数不会返回任何数据。

videos_list_most_popular返回print_response函数的结果。但由于该函数仅打印响应，并且实际上不返回任何内容，它将返回None，然后在执行videos_list_most_popular的下方返回，结果将为None。

它也会消失，因为你不会将该函数的结果分配给任何东西（看起来像response = videos_list_most_popular(...)）。

您需要更改videos_list_most_popular，以便它返回response，然后像我上面那样分配返回值。然后你可以执行你写的行。

来自Youtube API的最受欢迎的YouTube视频

1 个答案: