Question

我是Python 3的新手，正在使用Hackerrank上的"Breaking the Records" problem。当我使用字符串输入时，我的代码在IDLE中正常工作，但我不知道如何将Hackerrank的输入更改为像字符串一样“可用”的东西。基本上我尝试过的所有其他Hackerrank练习也遇到了同样的问题。

问题是对于输入，“第一行包含表示游戏数量的整数 n ，第二行包含 n 间隔分隔的整数s0，s1，... s（n-1）“

的各自值

这是我到目前为止尝试过的代码。

   select T1.RegionID
        , T1.RegionDescription 
        , T1.MaxSoldQuantity
        , N2.ProductName
        , N2.ProductID
   from (
      select NESTED.RegionID
         , NESTED.RegionDescription
         , max(NESTED.SoldQuantity) as MaxSoldQuantity
      from (
        select R.RegionID as RegionID
                    , R.RegionDescription as RegionDescription
                    , P.ProductID as ProductID
                    , P.ProductName as ProductName
                    , sum(OD.Quantity) as SoldQuantity
        from Region as R inner join Territories as T on R.RegionID = T.RegionID
                         inner join EmployeeTerritories as ET on T.TerritoryID = ET.TerritoryID
                         inner join Employees as E on ET.EmployeeID = E.EmployeeID
                         inner join Orders as O on E.EmployeeID = O.EmployeeID
                         inner join [Order Details] as OD on O.OrderID = OD.OrderID
                         inner join Products as P on OD.ProductID = P.ProductID
        group by R.RegionID, R.RegionDescription, P.ProductID, P.ProductName
    ) as NESTED
    group by NESTED.RegionID, NESTED.RegionDescription ) T1
  inner join (
     select R.RegionID as RegionID
                  , R.RegionDescription as RegionDescription
                  , P.ProductID as ProductID
                  , P.ProductName as ProductName
                  , sum(OD.Quantity) as SoldQuantity
      from Region as R inner join Territories as T on R.RegionID = T.RegionID
                       inner join EmployeeTerritories as ET on T.TerritoryID = ET.TerritoryID
                       inner join Employees as E on ET.EmployeeID = E.EmployeeID
                       inner join Orders as O on E.EmployeeID = O.EmployeeID
                       inner join [Order Details] as OD on O.OrderID = OD.OrderID
                       inner join Products as P on OD.ProductID = P.ProductID
      group by R.RegionID, R.RegionDescription, P.ProductID, P.ProductName
  ) N2 on N2.SoldQuantity = T1.MaxSoldQuantity

Answer 1

这就是我的所作所为：

#!/bin/python3 
import sys

def breakingRecords(score):
    # Complete this function
    min = -1
    minCount = 0
    maxCount = 0
    for s in score:
        if min == -1:
            min = s
            max = s
            continue
        if s < min:
            min = s
            minCount+=1
        if s > max:
            max = s
            maxCount+=1
    return maxCount, minCount

if __name__ == "__main__":
    n = int(input().strip())
    score = map(int,input().strip().split(' '))
    result = breakingRecords(score)
    print(" ".join(map(str, result)))

我认为我将原始代码部分保留在 - if __name__ == "__main__":

之下

Answer 2

  // Complete the breakingRecords function below.
static int[] breakingRecords(int[] scores) {
  int high, low;
  high = low = -1;
  int h,l;
  h = l = 0;
  int[] list = new int[2];
  low = scores[0];
for(int i=1; i<=scores.length; i++){
  if(high < scores[i -1]){
    high = scores[i -1];
    h++;
  }
if(i < scores.length){
    if(low > scores[i]){
        low = scores[i];
        l++;
      }
  }}
list[0] = h - 1;
list[1] = l ;
return list;
}

如何将Hackerrank上的输入转换为字符串？

2 个答案: