我有一个PHP表单,用户可以填写他们的门牌号和邮政编码,然后单击按钮将他们的地址自动填入空白字段。我使用的是Google Maps API,但收到错误消息。表单字段包含[object Object]而不是字符串值。
function getAddress(object) {
postcode = jQuery(object).parent().siblings('.address-finder-postcode').children('input').val();
housenumber = jQuery(object).parent().siblings('.address-finder-house').children('input').val();
street = jQuery(object).parent().siblings('.address-finder-street').children('input');
district = jQuery(object).parent().siblings('.address-finder-district').children('input');
town = jQuery(object).parent().siblings('.address-finder-town').children('input');
county = jQuery(object).parent().siblings('.address-finder-county').children('input');
if (postcode == '' || housenumber == '') {
alert('Please enter a postcode and house name or number');
return;
}
jQuery.ajax({
type: "POST",
url: '/wp-content/themes/wfal/page-templates/find-address.php',
data: {
'postcode': postcode
},
success: function(data) {
jQuery('input[name=address1]').val(housenumber);
jQuery('input[name=address2]').val(street);
jQuery('input[name=city]').val(town);
jQuery('input[name=county]').val(county);
console.log(data);
street.val(data.route);
if (data.locality != data.postal_town) {
district.val(data.locality);
}
town.val(data.postal_town);
county.val(data.administrative_area_level_2);
},
dataType: 'json'
});
}
jQuery(document).ready(function() {
jQuery('.address-finder-button').click(function() {
getAddress(this);
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="row">
<div class="half-width">
<p class="address-finder-house"><label for="address-finder-house">House name or number:</label><input type="text" name="address1" id="address-finder-house" value="" /></p>
</div>
<div class="half-width">
<p class="address-finder-postcode"><span class="title">Postcode:</span><input type="text" id="address-finder-postcode" value="" /></p>
<p><input type="button" value="Find Address" class="address-finder-button" value="" /></p>
</div>
<div class="half-width">
<span class="title">Street</span>
<p class="address-finder-street"><input type="text" id="address-finder-street" name="address2" value="" /></p>
</div>
</div>
<div class="row">
<div class="half-width">
<span class="title">Town/city</span>
<p class="address-finder-town"><input id="address-finder-town" name="city" type="text" value="" /></p>
</div>
<div class="half-width">
<span class="title">County</span>
<p class="address-finder-county"><input id="rem-mort" name="county" type="text" value="" /> </p>
</div>
</div>
<?php
// Get the postcode from the request
$postcode = $_REQUEST['postcode'];
// Get the latitude & longitude of submitted postcode
$postcode = urlencode($postcode);
$query = 'https://maps.googleapis.com/maps/api/geocode/json?address=' .
$postcode . '&sensor=false';
$result = json_decode(file_get_contents($query));
$lat = $result->results[0]->geometry->location->lat;
$lng = $result->results[0]->geometry->location->lng;
// Get the address based on returned lat & long
$address_url = 'https://maps.googleapis.com/maps/api/geocode/json?latlng=' . $lat . ',' . $lng . '&sensor=false';
$address_json = json_decode(file_get_contents($address_url));
$address_data = $address_json->results[0]->address_components;
foreach($address_data as $data):
$array[$data->types[0]] = $data->long_name;
endforeach;
echo json_encode($array);
?>
以下是我的控制台日志的截图 - prnt.sc/ii7xza。如您所见,数据未插入地址字段。他们留空了。
我在这里做错了什么?
由于
答案 0 :(得分:1)
在成功回调中设置值时,您将引用对象本身而不是数据。
jQuery('input[name=address1]').val(housenumber);
该实例中的housenumber是一个对象,最好的办法是在其上进行控制台登录并找出确切的参数。你应该结束的是
jQuery('input[name=address1]').val(housenumber.value);
或类似的东西。
如果您发布更多输出,我们可以确定准确的输入。
给出样本数据;
jQuery('input[name=address1]').val(housenumber);
应成为jQuery('input[name=address1]').val(data.street_number);
从截图中看,您只需使用ajax调用返回的密钥即可。您必须在密钥前加data.
,因为这是您将请求的返回数据传递给回调函数的方式。
$.ajax()
http://api.jquery.com/jQuery.ajax/上的文档
关于Ajax事件的文档,http://api.jquery.com/Ajax_Events/成功回调是一个事件。