Question

我的课程Sku有属性：

class Sku
{
    private string term_name;
    private string sku_name;
    private int sku_qty;

    public string Term_name
    {
        get { return term_name; }
        set { term_name = value; }
    }
    public string Sku_name
    {
        get { return sku_name; }
        set { sku_name = value; }
    }
    public int Sku_qty
    {
        get { return sku_qty; }
        set { sku_qty = value; }
    }
}

所以我创建了List<List<Sku>>：

List<List<Sku>> SplitChosenCopy = new List<List<Sku>>();

List<Sku> skus = new List<Sku>();
skus.Add(new Sku { Term_name = "301", Sku_name = "sku2", Sku_qty = 30 });
skus.Add(new Sku { Term_name = "302", Sku_name = "sku4", Sku_qty = 3 });

List<Sku> skus2 = new List<Sku>();
skus2.Add(new Sku { Term_name = "301", Sku_name = "sku7", Sku_qty = 30 });
skus2.Add(new Sku { Term_name = "302", Sku_name = "sku4", Sku_qty = 3 });

List<Sku> skus3 = new List<Sku>();
skus3.Add(new Sku { Term_name = "301", Sku_name = "sku2", Sku_qty = 9 });
skus3.Add(new Sku { Term_name = "302", Sku_name = "sku4", Sku_qty = 8 });

SplitChosenCopy.Add(skus);
SplitChosenCopy.Add(skus2);
SplitChosenCopy.Add(skus3);

如何比较SplitChosenCopy内的列表？例如，按属性Sku_name和Term_name？列表SplitChosenCopy[0]和SplitChosenCopy[2]将是重复的。

此类列表也不重复：

List<Sku> skus4 = new List<Sku>();
skus2.Add(new Sku { Term_name = "301", Sku_name = "sku2", Sku_qty = 30 });
skus2.Add(new Sku { Term_name = "302", Sku_name = "sku4", Sku_qty = 3 });

List<Sku> skus5 = new List<Sku>();
skus3.Add(new Sku { Term_name = "301", Sku_name = "sku4", Sku_qty = 9 });
skus3.Add(new Sku { Term_name = "302", Sku_name = "sku2", Sku_qty = 8 });

例如，我想将SplitChosenCopy中的每个列表与另一个列表进行比较并获取其索引：

foreach (List<Sku> sku in SplitChosenCopy)
{
    //compare list sku with lists in SplitChosenCopy
}

Answer 1

尝试以下代码：

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Data;
using System.Xml;
using System.Xml.Serialization;
using System.IO;


namespace ConsoleApplication23
{
    class Program
    {
        static void Main(string[] args)
        {
            List<List<Sku>> SplitChosenCopy = new List<List<Sku>>();

            List<Sku> skus = new List<Sku>();
            skus.Add(new Sku { Term_name = "301", Sku_name = "sku2", Sku_qty = 30 });
            skus.Add(new Sku { Term_name = "302", Sku_name = "sku4", Sku_qty = 3 });

            List<Sku> skus2 = new List<Sku>();
            skus2.Add(new Sku { Term_name = "301", Sku_name = "sku7", Sku_qty = 30 });
            skus2.Add(new Sku { Term_name = "302", Sku_name = "sku4", Sku_qty = 3 });

            List<Sku> skus3 = new List<Sku>();
            skus3.Add(new Sku { Term_name = "301", Sku_name = "sku2", Sku_qty = 9 });
            skus3.Add(new Sku { Term_name = "302", Sku_name = "sku4", Sku_qty = 8 });

            SplitChosenCopy.Add(skus);
            SplitChosenCopy.Add(skus2);
            SplitChosenCopy.Add(skus3);

            var results = SplitChosenCopy.GroupBy(x => x).ToList();

        }
    }
    class Sku : IEqualityComparer<Sku>
    {
        private string term_name;
        private string sku_name;
        private int sku_qty;

        public string Term_name
        {
            get { return term_name; }
            set { term_name = value; }
        }
        public string Sku_name
        {
            get { return sku_name; }
            set { sku_name = value; }
        }
        public int Sku_qty
        {
            get { return sku_qty; }
            set { sku_qty = value; }
        }

        bool IEqualityComparer<Sku>.Equals(Sku  a, Sku  b)
        {

            return  a.term_name.Equals(b.term_name) && a.sku_name.Equals(b.sku_name) && a.sku_qty.Equals(b.sku_qty);

        }
        int IEqualityComparer<Sku>.GetHashCode(Sku obj)
        {
            if (Object.ReferenceEquals(obj, null))
                return 0;

            return (obj.term_name + "^" +  obj.sku_name + "^" + obj.sku_qty.ToString()).GetHashCode() ;
        }
    }



}

如何比较List <list <some_class>＆gt;（）中的列表？

1 个答案: