Question

我可以在这个脚本上使用循环吗？我使用了相同的sql语句，但唯一的区别是字段的值（NAME）。

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    select 

distinct 

(select  VALUE 
from TABLE1 
where O_ID = a.O_ID 
and NAME ='Activity')Activity  ,

(select  VALUE 
from TABLE1 
where O_ID = a.O_ID 
and NAME ='code') code ,

(select  VALUE 
from TABLE1 
where O_ID = a.O_ID 
and NAME ='object')object,

from TABLE1 a
where a.O_ID   = 15850196

;

Answer 1

我不认为在你的情况下你会通过使用with子句获得足够的收益......但由于你无法创建函数，你可以按如下方式重新编写查询：

with 
Activities as (select O_ID , VALUE from TABLE1 where NAME ='Activity'), 
codes  as     (select O_ID , VALUE from TABLE1 where NAME ='code') ,
objects as    (select O_ID , VALUE from TABLE1 where NAME ='object') 
select 
(select VALUE from Activities where a.O_ID = O_ID) as Activity, 
(select VALUE from codes where a.O_ID = O_ID) as code, 
(select VALUE from objects where a.O_ID = O_ID) as object   
from TABLE1 a
where a.O_ID   = 15850196

或

with 
Activities as (select O_ID , VALUE from TABLE1 where NAME ='Activity'), 
codes  as     (select O_ID , VALUE from TABLE1 where NAME ='code') ,
objects as    (select O_ID , VALUE from TABLE1 where NAME ='object') 
select 
Activity.value, codes.value, objects.value 
from TABLE1 a,Activities, codes, objects    
where a.O_ID   = 15850196 and
      a.O_ID =  Activities.O_ID(+) and 
      a.O_ID =  codes.O_ID(+)  and 
      a.O_ID =  objects.O_ID(+)

Answer 2

这似乎是那些烦人的键/值表之一。您需要ID 15850196的活动，代码和对象，但由于不存在包含这些列的表，因此您必须在键/值表中查找每个值。

一个常见的解决方案是条件聚合：

select
  max(case when name ='Activity' then value end) as activity,
  max(case when name ='code' then value end) as code,
  max(case when name ='object' then value end) as object
from table1
where o_id = 15850196;

循环多个select语句 - oracle sql

2 个答案: