我试图提出一个查询,该查询可以确定字符串(varchar)中是否存在3个或更多数字的数字序列。这适用于SQL Server
示例字符串:" 521324567" 将返回此行数据,因为它具有序列" 4567"。
示例字符串:" 410747823" 不会返回此行数据,因为没有3个或更多数字的序列。
示例字符串:" 1274563619" 将返回此行数据,因为它具有序列" 456"。
我想如果它是一个固定长度的字符串,我可能会想到类似于下面的sql的东西。
Select num from numbers where substring(num,2,1)=
(select substring(num,1,1)) + 1
答案 0 :(得分:4)
只有7种可能的序列,所以:
time.sleep(4)
rawpage=driver.page_source #storing the webpage in variable
souppage=BeautifulSoup(rawpage,"html.parser") #parsing the webpage
tbody=souppage.find("table",{"id":"table_devicesensortable"}) #scrapping
如果算上select num
from numbers
where num like '%123%'
or num like '%234%'
or num like '%345%'
or num like '%456%'
or num like '%567%'
or num like '%678%'
or num like '%789%'
,那么你也可以为此添加一个条件。
答案 1 :(得分:1)
试试这个。我知道这有点复杂。但是Works动态
DECLARE @MyNum NVARCHAR(50) = '1274563619'
;WITH CTE
AS
(
SELECT
SeqNo = 1,
MyNum = @MyNum,
PosNum = SUBSTRING(@MyNum,1,1)
UNION ALL
SELECT
SeqNo = SeqNo +1,
MyNum,
PosNum = SUBSTRING(MyNum,SeqNo,1)
FROM CTE
WHERE SeqNo <= LEN(@MyNum)
)
SELECT
MyNum
FROM CTE C1
WHERE EXISTS
(
SELECT 1 FROM CTE C2
WHERE
(
C2.SeqNo = C1.SeqNo+1
AND
C2.PosNum = C1.PosNum+1
)
OR
(
C2.SeqNo = C1.SeqNo+2
AND
C2.PosNum = C1.PosNum+2
)
)
GROUP BY MyNum
HAVING COUNT(1)>2
答案 2 :(得分:0)
波希米亚语是正确的,但这里是选择列表的变体:
select num, case when
num like '%012%'
or num like '%123%'
or num like '%234%'
or num like '%345%'
or num like '%456%'
or num like '%567%'
or num like '%678%'
or num like '%789%'
or num like '%890%'
or num like '%901%'
then 'Yep' else 'Nope' end as is_there_a_sequence
from numbers
我还添加了012
和890
。虽然901
可能是一座过头的桥梁。
我希望这会有所帮助。