Question

我在同一个数据库中有两个mysql表。第一个表是＆＃39; coi_system＆＃39;第二，＆＃39; monthly_saving＆＃39; id是从第一个表引用的。我想将这两个表格数据显示在this table。

所以，＆＃39; monthly_saving＆＃39;应显示在Cost Saving Monthly html列中，引用“coi_system”的ID。但事实证明它显示了1月17日的所有数据。列中的每个结果使每个结果显示为like this。这是代码，

＆＃13;

<?php

  $result = mysqli_query($conn,"SELECT * FROM coi_system, monthly_saving where monthly_saving.id=coi_system.id"); 
  while ($row = mysqli_fetch_assoc($result)) {
    $accountcode=$row['accountcode'];
    $department=$row['department'];
    $person_in_charge=$row['person_in_charge'];
    $project_title=$row['project_title'];
    $objective=$row['objective'];
    $how_to_do=$row['how_to_do'];
    $activities=$row['activities'];
    $project_started=$row['project_started'];
    $project_completed=$row['project_completed'];
    $target_cost_saving=$row['target_cost_saving'];
    $costsaving_afterjustification=$row['costsaving_afterjustification'];
    $costsaving_monthly=$row['costsaving_monthly'];
    $sum_of_month=$row['sum_of_month'];
    $targetsaving_currentmonth=$row['targetsaving_currentmonth'];
    $avg_monthly_saving=$row['avg_monthly_saving'];
    $todays_date=$row['todays_date'];
    $current_month=$row['current_month'];
    $Jan=$row['Jan'];
    $Feb=$row['Feb'];
    $Mac=$row['Mac'];
    $Apr=$row['Apr'];
    $May=$row['May'];
    $Jun=$row['Jun'];
    $Jul=$row['Jul'];
    $Aug=$row['Aug'];
    $Sep=$row['Sep'];
    $Oct=$row['Oct'];
    $Nov=$row['Nov'];
    $Dis=$row['Dis'];
    $id=$row['id'];
  ?>

  <div class="scroll">
  

  <tr id="row1">
      <td> </td>
      <td id="accountcode_row1"><div> <?php echo $accountcode;?></div></td>
      <td id="department_row1"><div> <?php echo $department;?></div></td>
      <td id="pic_row1"><div> <?php echo $person_in_charge;?></div></td>
      <td id="protitle_row1"><div> <?php echo $project_title;?></div></td>
      <td id="objective_row1"><div> <?php echo $objective;?></div></td>
      <td id="howtodo_row1"><div><?php echo $how_to_do;?></div></td>
      <td id="activities_row1"><div> <?php echo $activities;?></div></td>
      <td id="prostart_row1"><div> <?php echo $project_started;?></div></td>
      <td id="procompl_row1"><div> <?php echo $project_completed;?></div></td>
      <td id="targetcost_row1"><div> <?php echo $target_cost_saving;?></div></td>
      <td id="costafter_row1"><div> <?php echo $costsaving_afterjustification;?></div></td>
      <td><div><?php echo $Jan;?></div></td>
      <td><div><?php echo $Feb;?></div></td>
      <td><div><?php echo $Mac;?></div></td>
      <td><div><?php echo $Apr;?></div></td>
      <td><div><?php echo $May;?></div></td>
      <td><div><?php echo $Jun;?></div></td>
      <td><div><?php echo $Jul;?></div></td>
      <td><div><?php echo $Aug;?></div></td>
      <td><div><?php echo $Sep;?></div></td>
      <td><div><?php echo $Oct;?></div></td>
      <td><div><?php echo $Nov;?></div></td>
      <td><div><?php echo $Dis;?></div></td>
      <td><div><?php echo $sum_of_month; ?></div></td>
      <td><div><?php echo $avg_monthly_saving; ?></div></td>
      <td><div><?php echo $todays_date; ?></div></td>
      <td><div><?php echo $current_month; ?></div></td>
      <td><div></div></td>
      <td><div> <?php echo $targetsaving_currentmonth;?></div></td>

＆＃13;

我不确定错误在哪里，但我尝试过这样写，$result = mysqli_query($conn,"SELECT * FROM coi_system, monthly_saving where id");但这不是解决方案。我真的需要有人帮助，因为我对mysqli并不擅长。谢谢你提前！

更新

这是来自＆＃39; coi_system＆＃39;的表monthly_saving和this。 id被引用的地方。已解决但新问题，目前只有2行结果出现，其中包含了每月一次的＆＃39;数据。其余的没有出现，因为他们没有任何月度节省＆＃39;数据。那么如何展示它们呢？

Answer 1

试试这个

SELECT * from coi_system, monthly_saving where monthly_saving.id=coi_system.id;

Answer 2

SELECT * FROM coi_system INNER JOIN monthly_saving ON 'monthly_saving.id' = 'coi_system.id'

Answer 3

SELECT coi_system.*, monthly_saving.* FROM coi_system RIGHT JOIN monthly_saving ON monthly_saving.id=coi_system.id;

如果每月保存为空，则右连接可以解决您的问题。

根据html表

3 个答案: