我正在制作一个vue项目,我想在我的组件中使用传单。我显示了地图,我可以添加标记但是当我尝试删除标记时遇到错误。我得到了
未捕获的TypeError:无法读取属性' _leaflet_id'未定义的 在n(leaflet.js:5) 在e.removeLayer(leaflet.js:5) 在HTMLInputElement.eval(VM119323 App.vue:74) 在HTMLInputElement.dispatch(jquery.js:3058) 在HTMLInputElement.eventHandle(jquery.js:2676)
<template>
<div id="app" class="container-fluid">
<div class="row">
<div class="col-md-9">
<div id="map" class="map" style="height: 781px;"></div>
</div>
<div class="col-md-3">
</div>
</div>
<router-view/>
</div>
</template>
<script>
export default {
name: "App",
data() {
return {
map: null,
markers: [],
mapSW: [0, 4096],
mapNE: [4096, 0],
tileLayer: null
};
},
mounted() {
this.initMap();
this.initLayers();
this.onClick();
this.onPopupOpen();
},
computed: {
popupContent: function() {
return "<input type='button' value='Delete' class='marker-delete-button' /> <br> <input type='button' value='Add Event' class='add-event'/>";
}
},
methods: {
initMap() {
this.map = L.map("map").setView([0, 0], 1);
this.tileLayer = L.tileLayer("/static/map/{z}/{x}/{y}.png", {
maxZoom: 4,
minZoom: 3,
continuousWorld: false,
noWrap: true,
crs: L.CRS.Simple
});
this.tileLayer.addTo(this.map);
this.map.on("click", this.onClick, this);
this.map.setMaxBounds(
L.LatLngBounds(L.latLng(this.mapSW), L.latLng(this.mapNW))
);
},
initLayers() {},
onClick(e) {
var newMarker = L.marker(e.latlng, {
draggable: true
})
.addTo(this.map)
.bindPopup(this.popupContent);
this.markers.push(newMarker);
newMarker.on("popupopen", this.onPopupOpen, this);
},
onPopupOpen(index) {
$(".marker-delete-button:visible").click(() => {
this.map.removeLayer(this.newMarker);
});
}
}
};
</script>
答案 0 :(得分:2)
newMarker
变量的范围应属于该组件,以便您以后可以将其删除。现在它只存在于onClick
方法中。您可以阅读有关变量范围here的更多信息。为了解决您的问题,您需要将newMarker
添加到data()
函数:
// ...
data() {
return {
// ...
tileLayer: null,
newMarker: null
};
},
// ...
onClick(e) {
this.newMarker = L
.marker(e.latlng, { draggable: true })
.addTo(this.map)
.bindPopup(this.popupContent);
this.markers.push(this.newMarker);
this.newMarker.on("popupopen", this.onPopupOpen, this);
},
onPopupOpen(index) {
$(".marker-delete-button:visible").click(() => {
this.map.removeLayer(this.newMarker);
});
}
您完成的代码将类似于:
<template>
<div id="app" class="container-fluid">
<div class="row">
<div class="col-md-9">
<div id="map" class="map" style="height: 781px;"></div>
</div>
<div class="col-md-3">
</div>
</div>
<router-view/>
</div>
</template>
<script>
export default {
name: "App",
data() {
return {
map: null,
markers: [],
mapSW: [0, 4096],
mapNE: [4096, 0],
tileLayer: null,
newMarker: null
};
},
mounted() {
this.initMap();
this.initLayers();
this.onClick();
this.onPopupOpen();
},
computed: {
popupContent: function() {
return "<input type='button' value='Delete' class='marker-delete-button' /> <br> <input type='button' value='Add Event' class='add-event'/>";
}
},
methods: {
initMap() {
this.map = L.map("map").setView([0, 0], 1);
this.tileLayer = L.tileLayer("/static/map/{z}/{x}/{y}.png", {
maxZoom: 4,
minZoom: 3,
continuousWorld: false,
noWrap: true,
crs: L.CRS.Simple
});
this.tileLayer.addTo(this.map);
this.map.on("click", this.onClick, this);
this.map.setMaxBounds(
L.LatLngBounds(L.latLng(this.mapSW), L.latLng(this.mapNW))
);
},
initLayers() {},
onClick(e) {
this.newMarker = L
.marker(e.latlng, { draggable: true })
.addTo(this.map)
.bindPopup(this.popupContent);
this.markers.push(this.newMarker);
this.newMarker.on("popupopen", this.onPopupOpen, this);
},
onPopupOpen(index) {
$(".marker-delete-button:visible").click(() => {
this.map.removeLayer(this.newMarker);
});
}
}
};
</script>
答案 1 :(得分:0)
您还可以做的是使用hasLayer方法,在删除标记之前验证标记是否确实在地图上,
if (this.map.hasLayer(this.newMarker)) this.map.removeLayer(this.newMarker);