合并node.js中的对象

Question

我有一些对象，我试图在Node.js中将它们合并在一起 第一个对象的格式如下

{ ids : [id, id, id, ....]}

对象的其余部分采用如下格式

{ postcode: '' , lat: '', lon: ''}, {postcode: '' , lat: '', lon: ''},....

我需要以类似于此

的格式合并它们

{ id: '', postcode: '', lat: '', lon:''}

我想知道是否可以在nodejs中做到这一点？

Answer 1

ECMAScript 2015（ES6）标准方法

Object.assign(obj1, obj2);

Answer 2

使用函数forEach。

  

假设对象都在同一个数组中。

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var array = [{ ids : ['5a6df69d84a1d08d9104c0b2', '5a6df69d84a1d08d9104c0b3', '5a6df69d84a1d08d9104c0b4']}, { postcode: 'BL9 9LS', lat: 53.5784531917354, lon: -2.30434868940289, admin_ward: 'E05000682' }, { postcode: 'SK3 0RH', lat: 53.4003081612165, lon: -2.19362957330647, admin_ward: 'E05000788' }, { postcode: 'BS1 5BQ', lat: 51.4564431573373, lon: -2.59829088044349, admin_ward: 'E05010892' }];

var result = array.slice(-(array.length - 1)); // Create a new Array removing the first position.
result.forEach((e, i) => e['id'] = array[0].ids[i] /* Add id from the first element*/);

console.log(result);

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分隔的对象

     

此方法修改源数组。

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var firstObject = { ids : ['5a6df69d84a1d08d9104c0b2', '5a6df69d84a1d08d9104c0b3', '5a6df69d84a1d08d9104c0b4']};
var array = [{ postcode: 'BL9 9LS', lat: 53.5784531917354, lon: -2.30434868940289, admin_ward: 'E05000682' }, { postcode: 'SK3 0RH', lat: 53.4003081612165, lon: -2.19362957330647, admin_ward: 'E05000788' }, { postcode: 'BS1 5BQ', lat: 51.4564431573373, lon: -2.59829088044349, admin_ward: 'E05010892' }];

array.forEach((e, i) => e['id'] = firstObject.ids[i]);

console.log(array);

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使用函数map。

  

假设对象都在同一个数组中。

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var array = [{ ids : ['5a6df69d84a1d08d9104c0b2', '5a6df69d84a1d08d9104c0b3', '5a6df69d84a1d08d9104c0b4']}, { postcode: 'BL9 9LS', lat: 53.5784531917354, lon: -2.30434868940289, admin_ward: 'E05000682' }, { postcode: 'SK3 0RH', lat: 53.4003081612165, lon: -2.19362957330647, admin_ward: 'E05000788' }, { postcode: 'BS1 5BQ', lat: 51.4564431573373, lon: -2.59829088044349, admin_ward: 'E05010892' }];

var result = array.slice(-(array.length - 1)); // Create a new Array removing the first position.
result = result.map((e, i) => ({ ...e, ...{'id': array[0].ids[i] } }) /* Add id from the first element*/);

console.log(result);

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分隔的对象

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var firstObject = { ids : ['5a6df69d84a1d08d9104c0b2', '5a6df69d84a1d08d9104c0b3', '5a6df69d84a1d08d9104c0b4']};
var array = [{ postcode: 'BL9 9LS', lat: 53.5784531917354, lon: -2.30434868940289, admin_ward: 'E05000682' }, { postcode: 'SK3 0RH', lat: 53.4003081612165, lon: -2.19362957330647, admin_ward: 'E05000788' }, { postcode: 'BS1 5BQ', lat: 51.4564431573373, lon: -2.59829088044349, admin_ward: 'E05010892' }];

var result = array.map((e, i) => ({ ...e, ...{ 'id': firstObject.ids[i] } }));

console.log(result);

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Answer 3

试试这个。 Object.assign会改变你的对象。

let idsObj = { ids : [id, id, id, ....]};

let postCodeArray = [{ postcode: '' , lat: '', lon: ''}, {postcode: '' , lat: '', lon: ''}];

postCodeArray.forEach((elem,index) => Object.assign(elem,{id: idsObj.ids[index]}));

Answer 4

您可以使用id。

添加对象

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var object1 = { ids: [23, 42] },
    postcodes = [{ postcode: 'XY' , lat: '11', lon: '22' }, { postcode: 'ZY' , lat: '33', lon: '44'}],
    merged = postcodes.map((o, i) => Object.assign({ id: object1.ids[i] }, o));
    
console.log(merged);

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