Question

最近我将我的代码库从.net core 1.0迁移到了2.0。之后我收到错误＆＃34;当随机使用System.Net.Http.HttpClient＆＃34; 时，服务器返回了无效或无法识别的响应错误。我在100个请求中的2个中收到此错误。

ALso如何调试它，因为它是随机发生的:(

Program.cs的

public class Program
    {
        public static void Main(string[] args)
        {
            var config = new ConfigurationBuilder()
            .AddJsonFile(Path.Combine(Directory.GetCurrentDirectory(),"hosting.json"), optional: false)
            .Build();

            var useHttps = false;

            bool.TryParse(config !=null  ? config["useHttps"] : "false", out useHttps);

            IWebHost host = null;
            if (useHttps)
            {
                var fileInfo = new FileInfo(config["certName"]);
                X509Certificate2 cert = new X509Certificate2(fileInfo.FullName, config["certPwd"]);

                host = new WebHostBuilder()
                    .UseContentRoot(Directory.GetCurrentDirectory())
                    .UseStartup<Startup>()
                    .UseKestrel(options =>
                    {
                        options.Listen(IPAddress.Loopback, 5000);
                        options.Listen(IPAddress.Any, 4430, listenOptions =>
                        {
                            listenOptions.UseHttps(cert);
                        });
                    })
                    .UseIISIntegration()
                    .Build();
            }
            else
            {
                host = new WebHostBuilder()
                    .UseStartup<Startup>()
                    .UseKestrel()
                    .UseContentRoot(Directory.GetCurrentDirectory())
                    .UseIISIntegration()
                    .UseUrls(config["url"])
                    .Build();

            }
            host.Run();


        }
    }

HTTP网络文件

public class NetworkExtensions
    {
        public static IConfiguration Configuration { get; set; }
        public static ILogger Log { get; set; }

        /// <summary>
        /// Flurl to get api
        /// </summary>
        /// <typeparam name="T"></typeparam>
        /// <param name="requestDto"></param> 
        /// <param name="rateLimit">This param is used to Perform OKTA api Retry </param> 
        /// <returns></returns>
        public static async Task<T> Get<T>(OktaRequestDto requestDto, OKTARateLimit rateLimit = null)
        {
            using (MiniProfiler.Current.Step("Okta : Get"))
            {

                // OKTA code execution starts here.
                string url = requestDto.BaseUrl
                    .AppendPathSegment(requestDto.ApiName + requestDto.Query);

                // Handle all querystring append.
                if (requestDto.QueryStrings != null && requestDto.QueryStrings.Count > 0)
                {
                    foreach (var querystring in requestDto.QueryStrings.Keys)
                    {
                        //FLURL is encoding the value, To ensure the value is passed correct, added true param to stop default behavior
                        url = url.SetQueryParam(querystring, requestDto.QueryStrings[querystring], true);
                    }
                }

                var response = await url.WithHeader("Authorization", requestDto.ApiKey).GetJsonAsync<T>();


                Log.Information("response  => " + JsonConvert.SerializeObject(response));

                return response;

                catch (FlurlHttpException ex)
                {
                    // there is an OKTA exception, return the default value, The exception is captured in the FLURLConfig
                    OneLoginException ole = new OneLoginException(ex, requestDto);
                    throw ole;

                }
                catch (Exception ex)
                {
                    throw ex;
                }
            }
        }
    }

收到错误：

{＆＃34; ClassName＆＃34;：＆＃34; Flurl.Http.FlurlHttpException＆＃34;，＆＃34; Message＆＃34;：＆＃34; GET https://xxx-yyy.oktapreview.com/api/v1/users/00ue1x6pgimMy2Zuf0h7失败。发送请求时发生错误。＆＃34;，＆＃34;数据＆＃34;：{}，＆＃34; InnerException＆＃34;：{＆＃34; ClassName＆＃34;：＆＃34;系统。 Net.Http.HttpRequestException＆＃34;，＆＃34; Message＆＃34;：＆＃34;发送请求时出错。＆＃34; ，＆＃34;数据＆＃34; ：{}，＆＃34;的InnerException＆＃34; {＆＃34;的ClassName＆＃34;：＆＃34; System.Net.Http.WinHttpException＆＃34;，的＆＃34;消息＆＃34 ;: ＆＃34;服务器返回了无效或无法识别的响应＆＃34; ，＆＃34;数据＆＃34;：{}，＆＃34; InnerException＆＃34;：null，＆＃34; HelpURL＆＃34 ;：空，＆＃34; StackTraceString＆＃34;：＆＃34; at System.Runtime.ExceptionServices.ExceptionDispatchInfo.Throw（）\ r \ n在System.Threading.Tasks.RendezvousAwaitable 1.GetResult()\r\n at System.Net.Http.WinHttpHandler.<StartRequest>d__105.MoveNext()","RemoteStackTraceString":null,"RemoteStackIndex":0,"ExceptionMethod":null,"HResult":-2147012744,"Source":"System.Private.CoreLib","WatsonBuckets":null,"NativeErrorCode":12152},"HelpURL":null,"StackTraceString":" at System.Runtime.ExceptionServices.ExceptionDispatchInfo.Throw()\r\n at System.Runtime.CompilerServices.TaskAwaiter.HandleNonSuccessAndDebuggerNotification(Task task)\r\n at System.Runtime.CompilerServices.ConfiguredTaskAwaitable 1.ConfiguredTaskAwaiter.GetResult（）\ r \ n在System.Net.Http.DiagnosticsHandler.d__2 .MoveNext（）\ r \ n ---在抛出异常的前一个位置的堆栈跟踪结束---在System.Runtime的System.Runtime.ExceptionServices.ExceptionDispatchInfo.Throw（）\ r \ n中的\ r \ n。 System.Net.Http.HttpClient.d__58.MoveNext（）\ r \的System.Runtime.CompilerServices.ConfiguredTaskAwaitable`1.ConfiguredTaskAwaiter.GetResult（）\ r \ n的CompilerServices.TaskAwaiter.HandleNonSuccessAndDebuggerNotification（任务任务）\ r \ n n ---抛出异常的前一个位置的堆栈跟踪结束---在System.Runtime.CompilerServices.TaskAwaiter.HandleNonSuccessAndDebuggerNotification的System.Runtime.ExceptionServices.ExceptionDispatchInfo.Throw（）\ r \ n中的\ r \ n任务）\ r \ n在Flurl.Http.FlurlRequest.d__19.MoveNext（）＆＃34;，＆＃34; RemoteStackTraceString＆＃34;：null，＆＃34; RemoteStackIndex＆＃ 34;：0，＆＃34; ExceptionMethod＆＃34;：空，＆＃34; HResult的＆＃34;： - 2147012744＆＃34;来源＆＃34;：＆＃34; System.Private.CoreLib＆＃34 ;, ＆＃34; WatsonBuckets＆＃34;：空}＆＃34; HELPURL＆＃34;：空}

Answer 1

我遇到了同样的问题，并且仍然存在，因此解决该问题的解决方案是：将客户端请求块包装在一次尝试中，并在发生错误的情况下多次进行处理，根据： https://docs.microsoft.com/en-us/azure/architecture/patterns/retry

使用System.Net.Http.HttpClient

1 个答案: