我正在尝试获取最后一个订单ID并将其设置为变量,因此我可以在另一个Order_Items
表中设置此ID
$generatedId=0;
if(isset($_POST['newOrder'])){
$costumerID = $_POST['CostumerID'];
$orderDateID = $_POST['orderDateID'];
$deliveryDateID = $_POST['deliveryDateID'];
$orderRemeraks = $_POST['orderRemeraks'];
$orderType = $_POST['orderType'];
echo $costumerID;
$query = "INSERT INTO `orders` (`costumerName`,`dateOfOrder`,`dateOfDelivery`,`remarks`,`type`,`status`)
VALUES ('$costumerID','$orderDateID','$deliveryDateID','$orderRemeraks','$orderType', 'open');";
$insertRow = $mysqli->query($query) or die ($mysqli->error.__LINE__);
$generatedId = $mysqli->insert_id;
if($insertRow){
$GLOBALS['generatedId'] = $mysqli->insert_id;
$msg = 'New Order was added ';
echo $msg;
echo $generatedId;
}
}
if(isset($_POST['newItem'])){
$item_Number = $_POST['item_Number'];
$itemQty = $_POST['itemQty'];
$itemKg = $_POST['itemKg'];
$itemRemarks = $_POST['itemRemarks'];
echo $generatedId;
$query = "INSERT INTO `item_number` (`order_id`, `item_number`, `quantity`,`quantity_kg`,` remarks`,`filling_status`)
VALUES('$generatedId', '$item_Number','$itemQty','$itemKg','$itemRemarks','not',);";
$insertRow = $mysqli->query($query) or die ($mysqli->error.__LINE__);
if($insertRow){
echo 'New Item was added ' ;
}
}
问题是$genertedId
打印的是初始0,因为我不能把它放在order_items表中,但是在第一次(echo $msg
之后,打印时它是'返回真实值;
谢谢
答案 0 :(得分:0)
$generatedId = mysqli_insert_id($mysqli);
if($insertRow){
$GLOBALS['generatedId'] = $generatedId;
$msg = 'New Order was added ';
echo $msg;
echo $generatedId;
}