Question

我想要这样的事情。

select car.name
from car
where 
(1 AND 2) IN (Select c.ConfigItemId from Contract c where c.ContractId = 
Car.ContractId)

看起来很简单，但我还没有找到解决方案。我唯一发现的是每个id匹配一行。

" AND (1) IN (Select c.ConfigItemId from Contract c where c.ContractId = 
Car.ContractId)"
 AND (2) IN (Select c.ConfigItemId from Contract c where c.ContractId = 
Car.ContractId)"

这样做的最佳方式是什么？

我想我需要澄清一下。我希望它对我发送的所有值都是必要的＆＃34; i，2＆＃34;存在于contract.configid。

Answer 1

您可以INNER JOIN和IN

来实现

select car.name from car
INNER JOIN Contract as c on c.ContractId = Car.ContractId
where c.ConfigItemId IN (1,2)
GROUP BY c.ContractId
HAVING COUNT(distinct c.ConfigItemId) > 1

Answer 2

从性能角度来看，EXISTS会更好，但是这样的东西可能会有效。

select car.name from car
join Contract c on c.ContractId = car.ContractId
where c.ConfigItemId in (1,2)

Answer 3

您可以使用简单的存在：

select  car.name
from    car
where   EXISTS (
                    SELECT  NULL
                    FROM    Contract c 
                    WHERE   c.ContractId = Car.ContractId
                        AND c.ConfigItemId IN (1, 2)
                    GROUP BY c.ContractId
                    HAVING   COUNT(distinct c.ConfigItemId) > 1
                )

几个ID发送到＆＃34; in＆＃34;？

3 个答案: