每个函数中都有jQuery

Question

我需要你们的一些帮助/指导我如何才能获得json结果中的数据。我如何从product_quotas1＆amp;获取数据？ product_quotas2？ 如果有人可以帮助或指导我解决这个问题，我将不胜感激。

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var myArrayNeed = {
  "3": {
    "id": "3",
    "state": "1",
    "charity_id": "3",
    "unmet_quotas": {
      "product_quotas1": {
        "product_id": "134",
        "quota": "32",
        "remaining_quota": "32",
        "progress": 0,
        "vegetarian": "0"
      },
      "product_quotas2": {
        "product_id": "153",
        "quota": "12",
        "remaining_quota": "12",
        "progress": 0,
        "vegetarian": "1"
      }
    }
  }
}
jQuery.each(myArrayNeed, function(index, value) {
  //console.log("index :" + index + "value :" + value);
  jQuery.each(value, function(subindex, subvalue) {
    // console.log("index :" + subindex + "value :" + subvalue);
    var unmet_quotas = value.unmet_quotas;
    //console.log('Unmet Quota : ' + unmet_quotas);
    jQuery.each(unmet_quotas, function(subsubindex, subsubvalue) {
      console.log("index :" , subsubindex , "value :" , subsubvalue);
    });
  });
});

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<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

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Answer 1

稍微调整一下代码

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var myArrayNeed={
    "3": {
        "id": "3",
        "state": "1",
        "charity_id": "3",
        "unmet_quotas": {
            "product_quotas1": {
                "product_id": "134",
                "quota": "32",
                "remaining_quota": "32",
                "progress": 0,
                "vegetarian": "0"
            },
            "product_quotas2": {
                "product_id": "153",
                "quota": "12",
                "remaining_quota": "12",
                "progress": 0,
                "vegetarian": "1"
            }
          }
        }
    }
    jQuery.each(myArrayNeed, function(index, value) {

  jQuery.each(value.unmet_quotas, function(subindex, subvalue) {
	console.log(subvalue);
   
  });
});

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<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

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第一个each将遍历您的＆＃34;对象＆＃34;属性只是此示例的一个属性3第二个each将遍历unmet_quotas的属性，这些属性是您想要的对象

Answer 2

试试这段代码

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var myArrayNeed = {
  "3": {
    "id": "3",
    "state": "1",
    "charity_id": "3",
    "unmet_quotas": {
      "product_quotas1": {
        "product_id": "134",
        "quota": "32",
        "remaining_quota": "32",
        "progress": 0,
        "vegetarian": "0"
      },
      "product_quotas2": {
        "product_id": "153",
        "quota": "12",
        "remaining_quota": "12",
        "progress": 0,
        "vegetarian": "1"
      }
    }
  }
}
//console.log(myArrayNeed);
jQuery.each(myArrayNeed, function(index, value) {
  jQuery.each(value.unmet_quotas, function(subindex, subvalue) {
    jQuery.each(subvalue, function(subsubindex, subsubvalue) {
      if (subsubindex == 'remaining_quota') {
        console.log("index :", subsubindex, "value :", subsubvalue);
        var remaining_quota = subsubvalue;
        alert(remaining_quota);
      }

    });
  });
});

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<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

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