当我在谷歌电子表格数据库的记录中输入日期时,我遇到了一个问题。不知道为什么,但当我删除日期时,它显示。我认为javascript无法从谷歌电子表格中读取日期?我尝试使用<? var data = getData(); ?>
<table id="tableShift2">
<caption>Team unknown</caption>
<th> Date and Time Plotted </th>
<th> LDAP </th>
<th> Date of VL </th>
<th> HD/WD </th>
<th> Action </th>
<? for (var q = 1; q < data.length; q++) {?>
<tr>
<td><?=data[q][1];?></td>
</tr>
<?}?>
</table>
但仍无效。请帮我解决这个问题。而且当我这样说时
function doGet() {
return HtmlService
.createTemplateFromFile('Index')
.evaluate();
}
function getData() {
return SpreadsheetApp
.openById('17lKIhONfEeNogsBhKtGr4zVaLgH0_199-3J3-0tAdcE')
.getActiveSheet()
.getDataRange()
.getValues();
}
显示日期。所以它在JS中不喜欢从数据库中读取日期。这就是为什么我需要你帮助的人如何完善编码。
Code.gs
<html>
<head>
<base target="_top">
</head>
<body>
<? var data = getData(); ?>
<div id="Options">
<label><b>Month</b></label>
<select id="selectMonth">
<option value="0">-Select Month-</option>
<option value="1">January</option>
<option value="2">February</option>
<option value="3">March</option>
<option value="4">April</option>
<option value="5">May</option>
<option value="6">June</option>
<option value="7">July</option>
<option value="8">August</option>
<option value="9">September</option>
<option value="10">October</option>
<option value="11">November</option>
<option value="12">December</option>
</select> -
<input type="radio" name="radioYear" id="radioYear" value="<?= new Date().getYear(); ?>"> <?= new Date().getYear(); ?>
<input type="radio" name="radioYear" id="radioYear2" value="<?= new Date().getYear()+1; ?>"> <?= new Date().getYear()+1; ?>
<button id="btnFetch" onclick="google.script.run.withSuccessHandler(fetchRecord).getData()">Fetch</button>
</div>
<div id="tables">
<table id="tableShift2">
<caption>Team unknown</caption>
<th> Date and Time Plotted </th>
<th> Name </th>
<th> Date of VL </th>
<th> HD/WD </th>
<th> Action </th>
</table>
</div>
<div id="date"></div>
<script
src="//ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js">
</script>
<script>
$(function() {
google.script.run.withSuccessHandler(showData)
.getData();
});
function showData(things) {
var table = $('#tableShift2');
for (var i = 0; i < things.length; i++) {
if (things[i][6] == '') {
table.append('<tr> <td>' + things[i][1] +
'</td> <td>' + things[i][2] +
'</td> <td>' + things[i][3] +
'</td> <td>' + things[i][4] +
'</td> <td ><button onclick=\'ApproveAndRefresh("' + things[i][0] + '","' + things[i][2] +
'")\' id="btnApprove">Approve</button> <button onclick=\'DeclineAndRefresh("' + things[i][0] + '","' + things[i][2] +
'")\' id="btnDecline">Decline</button></td></tr>');
}
}
}
function ApproveAndRefresh(data, data1){
google.script.run
.withSuccessHandler(refreshData)
.setApproved(data, data1);
}
function DeclineAndRefresh(data, data1){
google.script.run
.withSuccessHandler(refreshData)
.setDeclined(data, data1);
}
function refreshData(hl){
document.open();
document.write(hl);
document.close();
}
</script>
</body>
</html>
的index.html
{{1}}
答案 0 :(得分:1)
因此从.getData()
返回的数据是一个Object。 Google Apps脚本google.script.run
不支持此功能。你可以
return JSON.stringify(SpreadsheetApp.openById('17lKIhONfEeNogsBhKtGr4zVaLgH0_199-3J3-0tAdcE')
.getActiveSheet()
.getDataRange()
.getValues())
在您的脚本中,然后在SuccessHandler中:
function showData(things) {
things = JSON.parse(things)
//rest of your code...
}