我是WPF的新手,也是C#编程的新手(一般编程),我正在尝试开发WPF应用程序。
我试图通过几个与此类似的帖子,但我似乎找不到为什么这不起作用的答案。
所以,我很难理解MVVM架构,在多个用户控件绑定到单个<ContentControl />
之间切换的方式和内容。
从我目前所理解和阅读的内容来看,我必须像这样绑定视图模型:
<ContentControl Content="{Binding ApplicationViewModel}"/>
所以这就是我想要实现的目标:
左侧带有侧边栏菜单的ApplicationWindow.xaml
将在应用程序运行时始终显示,剩余空间为<ContentControl/>
。侧栏菜单上显示的按钮为:
MainView.xaml
用户控件,应为默认用户控件)SettingsView.xaml
用户控件)我知道我需要将按钮绑定到ICommand
命令,我理解RelayCommand.cs
类的概念。
因此,让我们跳进我的想法的简化代码,找出我需要理解的内容以及我在此过程中可能误解的内容。
MainView.xaml
和SettingsView.xaml
包含的内容现在并不重要,因为我只想弄清楚如何在我的应用程序中显示它们。
这是ApplicationWindow.xaml
:
<Window x:Class="WpfApp1.ApplicationWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
xmlns:local="clr-namespace:WpfApp1"
xmlns:v="clr-namespace:WpfApp1.View"
xmlns:vm="clr-namespace:WpfApp1.ViewModel"
mc:Ignorable="d"
Title="ApplicationWindow" Height="1080" Width="1920"
WindowStyle="None" WindowState="Maximized">
<Window.Resources>
<DataTemplate DataType="{x:Type vm:MainViewModel}">
<v:MainView/>
</DataTemplate>
<DataTemplate DataType="{x:Type vm:SettingsViewModel}">
<v:SettingsView/>
</DataTemplate>
</Window.Resources>
<DockPanel>
<!--Menu bar on the left-->
<Border DockPanel.Dock="Left">
<StackPanel Orientation="Vertical" Background="Gray" Width="120">
<Button Content="Main" Command="{Binding ShowMainCommand}"/>
<Button Content="Settings" Command="{Binding ShowSettingsCommand}"/>
<Button Content="Exit" Command="{Binding ExitApplicationCommand}"/>
</StackPanel>
</Border>
<!--The content control that view the current view-->
<ContentControl Content="{Binding ApplicationViewModel}"/>
</DockPanel>
</Window>
注意:通过覆盖OnStartup()方法,在App.xaml.cs中将DataContext设置为ApplicationViewModel.cs
。
public partial class App : Application
{
protected override void OnStartup(StartupEventArgs e)
{
base.OnStartup(e);
ApplicationWindow app = new ApplicationWindow
{
DataContext = new ApplicationViewModel()
};
app.Show();
}
}
这是ApplicationViewModel.cs
:
public class ApplicationViewModel : ViewModelBase
{
#region Fields
private List<ViewModelBase> _viewModels;
private ViewModelBase _currentViewModel;
private ICommand _showMainCommand;
private ICommand _showSettingsCommand;
private ICommand _exitApplicationCommmand;
#endregion
#region Constructor
public ApplicationViewModel()
{
ViewModels = new List<ViewModelBase>
{
new MainViewModel(),
new SettingsViewModel()
};
CurrentViewModel = ViewModels[0];
}
#endregion
#region Public Properties
public List<ViewModelBase> ViewModels
{
get
{
return _viewModels;
}
set
{
if (_viewModels != value)
{
_viewModels = value;
OnPropertyChanged(nameof(ViewModels));
}
}
}
public ViewModelBase CurrentViewModel
{
get
{
return _currentViewModel;
}
set
{
if(_currentViewModel != value)
{
_currentViewModel = value;
OnPropertyChanged(nameof(CurrentViewModel));
}
}
}
#endregion
#region Commands
public ICommand ShowMainCommand
{
get
{
if(_showMainCommand == null)
{
_showMainCommand = new RelayCommand(action => ShowMain());
}
return _showMainCommand;
}
}
public ICommand ShowSettingsCommand
{
get
{
if (_showSettingsCommand == null)
{
_showSettingsCommand = new RelayCommand(action => ShowSettings());
}
return _showSettingsCommand;
}
}
public ICommand ExitApplicationCommand
{
get
{
if (_exitApplicationCommmand == null)
{
_exitApplicationCommmand = new RelayCommand(action => ExitApplication());
}
return _exitApplicationCommmand;
}
}
#endregion
#region Private Methods
private void ShowMain()
{
CurrentViewModel = ViewModels[0];
}
private void ShowSettings()
{
CurrentViewModel = ViewModels[1];
}
private void ExitApplication()
{
MessageBoxResult result = MessageBox.Show("Are you sure you want to exit?", "Exit", MessageBoxButton.YesNo);
if (result == MessageBoxResult.Yes)
{
System.Windows.Application.Current.Shutdown();
}
}
#endregion
}
因此,根据我的理解,ApplicationWindow.xaml
应该能够确定从CurrentViewModel
设置的内容中显示哪个视图。
为了获取信息(或错过信息),这里有ViewModelBase.cs
:
public class ViewModelBase : INotifyPropertyChanged
{
#region INotifyPropertyChanged
public event PropertyChangedEventHandler PropertyChanged;
protected virtual void OnPropertyChanged([CallerMemberName] string propertyName = null)
{
PropertyChanged?.Invoke(this, new PropertyChangedEventArgs(propertyName));
}
#endregion
}
RelayCommand.cs
:
public class RelayCommand : ICommand
{
#region Fields
private readonly Action<object> _execute;
private readonly Predicate<object> _canExecute;
#endregion
#region Constructors
public RelayCommand(Action<object> execute, Predicate<object> canExecute)
{
if (execute == null)
throw new ArgumentNullException("execute");
_execute = execute;
_canExecute = canExecute;
}
public RelayCommand(Action<object> execute) : this(execute, null)
{
}
#endregion
#region ICommand
public bool CanExecute(object parameters)
{
return _canExecute == null ? true : _canExecute(parameters);
}
public event EventHandler CanExecuteChanged
{
add { CommandManager.RequerySuggested += value; }
remove { CommandManager.RequerySuggested -= value; }
}
public void Execute(object parameters)
{
_execute(parameters);
}
#endregion
}
我希望我对你的思考过程很清楚,你们中的一位聪明的程序员可以帮助解决这个问题,并帮助我理解为什么这不是我想要的结果。
如果我想要做的事情比Elon Musk关于制作多行星的项目更难,请随意解释原因并建议我更好的方式
答案 0 :(得分:0)
您的内容控件绑定应指向切换ViewModels时更改的实际属性
<ContentControl Content="{Binding CurrentViewModel}"/>