当查询中包含HAVING子句时，laravel中的COUNT(*)函数崩溃。
基本上它发生的是该函数从select中删除所有内容并添加HAVING并且from redis import Redis
from collections import MutableMapping
from pickle import loads, dumps
class RedisStore(MutableMapping):
def __init__(self, engine):
self._store = Redis.from_url(engine)
def __getitem__(self, key):
return loads(self._store[dumps(key)])
def __setitem__(self, key, value):
self._store[dumps(key)] = dumps(value)
def __delitem__(self, key):
del self._store[dumps(key)]
def __iter__(self):
return iter(self.keys())
def __len__(self):
return len(self._store.keys())
def keys(self):
return [loads(x) for x in self._store.keys()]
def clear(self):
self._store.flushdb()
d = RedisStore('redis://localhost:6379/0')
d['a'] = {'b': 1, 'c': 10}
print repr(d.items())
# this will not work: (it updates a temporary copy and not the real data)
d['a']['b'] = 2
print repr(d.items())
# this is how to update sub-structures:
t = d['a']
t['b'] = 2
d['a'] = t
print repr(d.items())
del d['a']
# Here is another way to implement dict-of-dict eg d['a']['b']
d[('a', 'b')] = 1
d[('a', 'b')] = 2
print repr(d.items())
# Hopefully you do not need the equivalent of d['a']
print repr([{x[0][1]: x[1]} for x in d.items() if x[0][0] == 'a'])
del d[('a', 'b')]
del d[('a', 'c')]
子句不再看到别名。
有没有解决方法呢？