Question

我想使用TabbedPanel小部件删除按钮上的选项卡。我的面板上有两个标签，我想删除第二个标签，以便面板只有一个标签。

from kivy.app import App
from kivy.uix.tabbedpanel import TabbedPanel
from kivy.lang import Builder

Builder.load_string("""

<Test>:
    size_hint: .5, .5
    pos_hint: {'center_x': .5, 'center_y': .5}
    do_default_tab: False

    TabbedPanelItem:
        text: 'first tab'
        Label:
            text: 'First tab content area'
    TabbedPanelItem:
        text: 'tab2'
        BoxLayout:
            Label:
                text: 'Second tab content area'
            Button:
                text: 'Button that deletes tab 2'
                background_color: (1, 0, 0, 1)

""")


class Test(TabbedPanel):
    pass


class TabbedPanelApp(App):
    def build(self):
        return Test()


if __name__ == '__main__':
    TabbedPanelApp().run()

Answer 1

一种可能的解决方案是通过传递remove_widget()来使用TabbedPanelItem，但为此我们可以搜索文本，但在此之前我们会切换到另一个标签。

from kivy.app import App
from kivy.uix.tabbedpanel import TabbedPanel
from kivy.lang import Builder

Builder.load_string("""

<Test>:
    size_hint: .5, .5
    pos_hint: {'center_x': .5, 'center_y': .5}
    do_default_tab: False

    TabbedPanelItem:
        text: 'first tab'
        Label:
            text: 'First tab content area'
    TabbedPanelItem:
        text: 'tab2'
        BoxLayout:
            Label:
                text: 'Second tab content area'
            Button:
                text: 'Button that deletes tab 2'
                background_color: (1, 0, 0, 1)
                on_press: root.removeTab('tab2')

""")


class Test(TabbedPanel):
    def removeTab(self, name):
        tab = None
        for i in self.tab_list:
            if i.text == name:
                tab = i
                break
        if tab:
            self.switch_to(self.default_tab)
            self.remove_widget(tab)


class TabbedPanelApp(App):
    def build(self):
        return Test()


if __name__ == '__main__':
    TabbedPanelApp().run()

Python KIVY：删除选项卡

1 个答案: