Question

所以我有这个函数创建了一些textareas，具体取决于它是什么月份。

例如：

如果是'二月'，则会创建28'textareas'。
如果是'March'，则会创建31'textareas'等等。

当用户点击'textareas'然后点击表单按钮时，textareas的值会插入到MySQL数据库中。

我现在的问题是进入数据库的值不是textareas的值，例如2018-02-19，始终是2018-02-28。

功能：

function daysInMonth(month, year) {
    var days;
    switch (month) {
        case 1: // Feb, our problem child
            var leapYear = ((year % 4 == 0) && (year % 100 != 0)) || (year % 400 == 0);
            days = leapYear ? 29 : 28;
            break;
        case 3:
        case 5:
        case 8:
        case 10:
            days = 30;
            break;
        default:
            days = 31;
    }
    return days;
}

var showDate = new Date();
var months = ["January", "February", "March", "April", "May", "June",
    "July", "August", "September", "October", "November", "December"
];
var weeks = ["Sunday", "Monday", "Tuseday", "Wednesday", "Thursday", "Friday", "Saturday"];

function drawTable(forDate) {
    var daysInMonth = new Date(forDate.getFullYear(), forDate.getMonth() + 1, 0).getDate();
    var cellsToDraw = daysInMonth;
    var newdate = forDate.getFullYear() + "-" + ("0" + (forDate.getMonth() + 1)).slice(-2);
    var table = document.getElementById("table");
    table.innerHTML = "";
    for (var r = 0; r < (daysInMonth / 7); r++) {
        var newRow = document.createElement("tr");
        table.appendChild(newRow);
        for (var c = 0; c < 31 && cellsToDraw > 0; c++) {
            var day1 = ("0" + (c + 1)).slice(-2);
            var textarea = document.createElement("textarea");
            textarea.setAttribute("type", "button");
            textarea.setAttribute("name", "day");
            textarea.setAttribute("value", newdate + "-" + day1);
            textarea.setAttribute("placeholder", day1);
            newRow.appendChild(textarea);
            textarea.setAttribute("name", "day");
            textarea.setAttribute("day", newdate + "-" + day1)
            textarea.innerHTML = newdate + "-" + day1;
            cellsToDraw--;
        }
    }
}

window.onload = function() {
    document.getElementById("displayingMonth").innerHTML = months[showDate.getMonth()];
    drawTable(showDate);
};

HTML：

<form class="" action="insert.php" method="post">
    <table id="table">
        <input id="day"type="hidden" name="day" value="">
        <input id="btn"  type="submit" name="" value="Press">
</form>

PHP

$day = mysqli_real_escape_string($conn, $_request['day']);
for ($i = 1; $i < count($day); $i++) {
    $stmt = "INSERT INTO calendar (day) VALUES('$day[$i])')";
    if (empty($day)) {
        $_SESSION['error'] = "Error";

        header('Location: insert.php', true, 303);
        exit();
    } else {
        if (mysqli_query($conn, $stmt)) {
            header('Location: insert.php', true, 303);
            exit;
        } else {
            $error= "Error: " .mysqli_error($conn);
            echo "$error";

        }
    }
}

Answer 1

这是因为发送到insert.php的数据看起来像这样（使用网络标签检查）

day=2018-02-01&day=2018-02-02&day=2018-02-03&day=2018-02-04&day=2018-02-05&day=2018-02-06&day=2018-02-07&day=2018-02-08&day=2018-02-09&day=2018-02-10&day=2018-02-11&day=2018-02-12&day=2018-02-13&day=2018-02-14&day=2018-02-15&day=2018-02-16&day=2018-02-17&day=2018-02-18&day=2018-02-19&day=2018-02-20&day=2018-02-21&day=2018-02-22&day=2018-02-23&day=2018-02-24&day=2018-02-25&day=2018-02-26&day=2018-02-27&day=2018-02-28

由于相同的密钥名称，它似乎占用了最后一个值。

不是直接提交表单，而是使用ajax提交表单并以数组或对象的形式发送数据

Answer 2

在这种情况下，您的日期字段应命名为数组。如果将多个字段命名为day，则它将作为单个字段获取具有相同名称的最后一个字段值。所以你必须改变一行，它会很好地工作。

 textarea.setAttribute("name", "day[]");

Answer 3

的JavaScript

是的，首先让我们开始使用JavaScript。

function drawTable(forDate) {
    // Days in a month
    const daysInMonth = new Date(
        forDate.getFullYear(),
        forDate.getMonth() + 1,
        0
    ).getDate();
    // 28

    // Start of a date
    const date = [
        forDate.getFullYear(),
        (forDate.getMonth() + 1 + '').padStart(2, 0)
    ]
    .join('-');
    // 2018-02

    // Reset the table
    const table = document.getElementById("table");
    table.innerHTML = "";

    // For each day of the month
    // Start at one, go until day > daysInMonth. e.g. (1 -> 28)
    for (let day = 1; day <= daysInMonth; day++) {
        const dateString = date + '-' + (day + '').padStart(2, 0);

        // Create the elements.
        const row = document.createElement("tr");
        const cell = document.createElement("td");
        const textarea = document.createElement("textarea");

        textarea.setAttribute("name", "day[]");
        textarea.setAttribute("value", dateString);
        textarea.innerHTML = dateString;
        textarea.setAttribute("placeholder", day);

        // These do nothing.
        // textarea.setAttribute("type", "button");
        // textarea.setAttribute("day", dateString)

        // Stack the children into the table.
        cell.appendChild(textarea);
        row.appendChild(cell);
        table.appendChild(row);
    }

    return table;
}

PHP

现在，让我们继续PHP。我首先要查看代码中的问题。

// Currently 'day' is an array.
// So this will throw an error.
$day = mysqli_real_escape_string($conn, $_request['day']);

// For every '$day[$i]' in '$day'
for ($i = 1; $i < count($day); $i++) {
    // $day is still an array.
    if (empty($day)) {
        $_SESSION['error'] = "Error";

        // The problem that you'll face here is that
        // one empty day fails the rest of the days
        header('Location: insert.php', true, 303);
        exit();
    } else {
        if (mysqli_query($conn, "INSERT INTO calendar (day) VALUES('$day[$i])')")) {
            // Here this will stop on the first '$day[$i]'
            header('Location: insert.php', true, 303);
            exit;
        } else {
            $error= "Error: " .mysqli_error($conn);
            echo "$error";
        }
    }
}

现在，我将看一个可能的解决方案。

// Currently 'day' is an array.
$days = $_request['day'];

// This is how we can carry our errors.
$error = array();

// For every 'day' in the 'days' array.
if (is_array($days))
foreach ($days as $day) {
    // Escape the day.
    $day = mysqli_real_escape_string($conn, $day);

    // Now this will work as expected.
    if (empty($day)) {
        // We shall use the $error array.
        $error[] = array(
            'day' => $day,
            'error' => 'day was empty'
        );
    }

    // Else if there is an error in the SQL query.
    else if (
        !mysqli_query(
            $conn,
            // You see how the '$day' variable is used
            "INSERT INTO calendar (day) VALUES('$day)')"
        )
    ) {
        // We shall use the $error array again here.
        $error[] = array(
            'day' => $day,
            'error' => mysqli_error($conn)
        );
    }
}

// If there was an error.
if (count($error)) {
    // Print the errors.
    print_r($error);
}

// Do your redirect.
header('Location: insert.php', true, 303);

HTML

最后，让我们看一下HTML。我首先要查看代码中的问题。

<!-- You do not need to define the blank 'class' -->
<form class="" action="insert.php" method="post">
    <!-- You should close the <table> tag. -->
    <table id="table">

    <!-- This is currently unneeded and could hinder the php. -->
    <input id="day"type="hidden" name="day" value="">

    <!-- You do not need to define the blank 'name' -->
    <input id="btn" type="submit" name="" value="Press">
</form>

现在，我将看一个可能的解决方案。

<form action="insert.php" method="post">
    <table id="table"></table>
    <input id="btn" type="submit" value="Press" />
</form>

*注意：*我没有尝试过这段代码。

如何通过JS从html textarea获取日期值

3 个答案:

的JavaScript

PHP

HTML