Question

我有下面的代码段

func getDeviceUUID() -> String {
        guard let uuid = UIDevice.current.identifierForVendor?.uuidString else {
            assertionFailure("Nil while unwrapping UIDevice.current.identifierForVendor?.uuidString")
            return ""}
        return uuid
    }

print(getDeviceUUID()) //50E6548C-0BB4-4979-8F5F-DFAD422BEB26

如何制作foreach ($response as $sms) { $receiver = "(".$sms['from'].",\"".$sms['body']."\",".$sms['timestamp'].")"; $res .=$receiver.","; } $res = substr($res, 0, -1); - 变量并在此代码之外使用它？

由于

Answer 1

您可以在循环外创建一个数组，并从循环中将每个$sms['from']推送到该数组。循环完成后，它将包含所有项目。

$sms_from = [];  

foreach ($response as $sms) {
    $sms_from[] = $sms['from'];
    $receiver = "
     (".$sms['from'].",\"".$sms['body']."\",".$sms['timestamp'].")";                     
    $res .=$receiver.",";
}
$res = substr($res, 0, -1);

var_dump($sms_from);// contains all the $sms['from']

从字符串php生成变量

1 个答案: