想象一下Entity Framework数据库中的一行5个数值,我如何检索该行的前2列,包括列的名称及其值?最好使用LINQ。
例如:
a b c d e
0 4 5 9 2
前2个值是9和5.我想检索值和列名称c和d。
更实际的例子:
var row = table.Where(model => model.Title.Contains(a.Title));
这一行会给我一行包含许多数值。 我想要的东西如下,
row.list().OrderByDescendingOrder().top(2);
答案 0 :(得分:0)
我不知道如何在linq中执行此操作,但这是一个SQL Server查询:
select t.*, v2.*
from t cross apply
(values ('a', a), ('b', b), ('c', c), ('d', d), ('e', e)
) v(col, val) cross apply
(select max(case when seqnum = 1 then val end) as val1,
max(case when seqnum = 1 then col end) as col1,
max(case when seqnum = 2 then val end) as val2,
max(case when seqnum = 3 then col end) as col2
from (select v.*, row_number() over (order by val desc) as seqnum
from v
) v
) v2;
编辑:
当然,您可以使用大量case
表达式来获取最大值:
select t.*,
(case when a >= b and a >= c and a >= d and a >= e then a
when b >= c and b >= d and b >= e then b
when c >= d and c >= e then c
when d >= e then d
else e
end) as max_value,
(case when a >= b and a >= c and a >= d and a >= e then 'a'
when b >= c and b >= d and b >= e then 'b'
when c >= d and c >= e then 'c'
when d >= e then 'd'
else 'e'
end) as max_value_col
from t;
问题是将此扩展到 second 值,尤其是在存在重复值的情况下。
答案 1 :(得分:0)
看起来你想要pivot这个数据,但使用Linq而不是T-SQL。 (或其他一些SQL方言)
执行此操作的基本模式是使用SelectMany
将每行转换为
一组键/值对,您可以OrderByDescending
开启。
以下是一种有点通用的模式:
// The values that we want to query.
// In your case, it's essentially the table that you're querying.
// I used an anonymous class for brevity.
var values = new[] {
new { key = 99, a = 0, b = 4, c = 5, d = 9, e = 2 },
new { key = 100, a = 0, b = 5, c = 3, d = 2, e = 10 }
};
// The query. I prefer to use the linq query syntax
// for actual SQL queries, but you should be able to translate
// this to the lambda format fairly easily.
var query = (from v in values
// Transform each value in the object/row
// to a name/value pair We include the key so that we
// can distinguish different rows.
// Because we need this query to be translated to SQL,
// we have to use an anonymous class.
from column in new[] {
new { key = v.key, name = "a", value= v.a },
new { key = v.key, name = "b", value= v.b },
new { key = v.key, name = "c", value= v.c },
new { key = v.key, name = "d", value= v.d },
new { key = v.key, name = "e", value= v.e }
}
// Group the same row values together
group column by column.key into g
// Inner select to grab the top two values from
// each row
let top2 = (
from value in g
orderby value.value descending
select value
).Take(2)
// Grab the results from the inner select
// as a single-dimensional array
from topValue in top2
select topValue);
// Collapse the query to actual values.
var results = query.ToArray();
foreach(var value in results) {
Console.WriteLine("Key: {0}, Name: {1}, Value: {2}",
value.key,
value.name,
value.value);
}
但是,由于您只有一行,因此逻辑变得更加简单:
// The value that was queried
var value = new { key = 99, a = 0, b = 4, c = 5, d = 9, e = 2 };
// Build a list of columns and their corresponding values.
// You could even use reflection to build this list.
// Additionally, you could use C# 7 tuples if you prefer.
var columns = new[] {
new { name = "a", value = value.a },
new { name = "b", value = value.b },
new { name = "c", value = value.c },
new { name = "d", value = value.d },
new { name = "e", value = value.e }
};
// Order the list by value descending, and take the first 2.
var top2 = columns.OrderByDescending(v => v.value).Take(2).ToArray();
foreach(var result in top2) {
Console.WriteLine("Column: {0}, Value: {1}", result.name, result.value);
}
答案 2 :(得分:0)
所以你有一个项目集合,可以在其中一个属性上进行排序,并且你希望集合中的两个项目具有此排序属性的最大值?
var result = myItems
.OrderByDescending(myItem => myItem.MyProperty)
.Take(2);
单词:按照MyProperty的降序排序整个集合,并从结果中取两个项目,这两个项目是MyProperty的最大值。
这将返回两个完整的myItem对象。通常,将更多属性从对象传输到本地内存并不是一个好主意,而不是实际计划使用。使用“选择”确保仅传输您计划使用的值:
var bestSellingProducts = products
.OrderByDescending(product=> product.Orders.Count())
.Select(product => new
{ // select only the properties you plan to use, for instance
Id = product.Id,
Name = product.Name,
Stock = product.Stock
Price = product.Price,
});
.Take(2);