我有一些视频课程,我想用Python以特定的方式重命名。这是一个示例文件名:
3D Graphics - Crash Course Computer Science #27-TEAtmCYYKZA.en"
我想选择" 27"并将其移动到文件名的开头,并删除" Crash Course Computer Science#"和" -TEAtmCYYKZA.en"完全是一部分。所以,我想要的输出是:
27 - 3D Graphics
另外两个例子:
Advanced CPU Designs - Crash Course Computer Science #9-rtAlC5J1U40
Boolean Logic & Logic Gates - Crash Course Computer Science #3-gI-qXk7XojA
到:
9 - Advanced CPU Designs
3 - Boolean Logic & Logic Gates
我知道如何删除部分,但我可以找到如何选择"#number"子。我发现了一个.split()
函数,但我再也看不出它是如何使它工作的。
这是我到目前为止写的内容,但我已经陷入了早期阶段。
import os
def rename():
file_list = os.listdir(r"D:\Downloads\New folder")
for file_name in file_list:
os.rename(file_name, )
rename()
答案 0 :(得分:4)
考虑到你的例子,这很容易做到,没有正则表达式,如:
def transform_name(filename):
number = filename.split('#')[1].split('-')[0].strip()
name = filename.split('-')[0].strip()
return '{} - {}'.format(number, name)
os.rename(existing_filename, transform_name(existing_filename))
test_in = (
"3D Graphics - Crash Course Computer Science #27-TEAtmCYYKZA.en",
"Advanced CPU Designs - Crash Course Computer Science #9-rtAlC5J1U40",
"Boolean Logic & Logic Gates - Crash Course Computer Science #3-gI-qXk7XojA",
)
desired_out = (
"27 - 3D Graphics",
"9 - Advanced CPU Designs",
"3 - Boolean Logic & Logic Gates",
)
for data in zip(test_in, desired_out):
assert transform_name(data[0]) == data[1], "{} != {}".format(
transform_name(data[0]), data[1])
答案 1 :(得分:1)
我喜欢@StephenRauch
没有正则表达式的答案,这只是为了显示另一个选项。
>>> import re
>>> REGEX = re.compile(r'(?P<name>.+) - .+ #(?P<number>\d+)')
>>> test_in = (
... "3D Graphics - Crash Course Computer Science #27-TEAtmCYYKZA.en",
... "Advanced CPU Designs - Crash Course Computer Science #9-rtAlC5J1U40",
... "Boolean Logic & Logic Gates - Crash Course Computer Science #3-gI-qXk7XojA",
... )
>>> for line in test_in:
... m = REGEX.match(line)
... if m:
... print('{number} - {name}'.format(**m.groupdict()))
...
27 - 3D Graphics
9 - Advanced CPU Designs
3 - Boolean Logic & Logic Gates