Question

使用PHP，我试图捕获REST调用中返回的错误描述并在javascript警报中将其抛出。

以下是XML错误响应：

<?xml version="1.0" encoding="utf-8"?>
<get_response xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
    <number_results>0</number_results>
    <search_criteria xsi:type="Forte.RestApi.Common.Models.v3.SearchRestrictions">
        <page_size>50</page_size>
        <page_index>0</page_index>
        <home_organization_id>org_334277</home_organization_id>
    </search_criteria>
    <response>
        <environment>live</environment>
        <response_desc>Error[1]: The content in the query string produced errors while parsing. Check that the content is correctly formatted. Error[2]: Error converting value '2018-02-31'. Field: 'end_au_updated_date'</response_desc>
    </response>
    <links>
        <self>https://api.forte.net/v3/paymethods/?filter=start_au_updated_date+eq+%272018-02-01%27+and+end_au_updated_date+eq+%272018-02-31%27</self>
    </links>
</get_response>

以下是我的工作原理：

$response = curl_exec($ch);

if (strpos($response, 'Error') !== false) {
echo "<script language='javascript'>alert",($response["response"]["response_desc"]),";</script>";
die;
}

我想要捕获的值是＆＃34; response_desc＆＃34;字段。

我错过了什么？

Answer 1

您可以使用let div = document.createElement("div"); div.innerHTML = data; document.getElementsByTagName("body")[0].appendChild(div);来获取字符串（而不是SimpleXML）：

$response["response"]["response_desc"]

输出：

$xml = simplexml_load_string($response);
echo (string)$xml->response->response_desc;

PHP-如何捕获XML错误描述

1 个答案: