如何在CakePHP 3.5中以一种形式将两个表单与两个不同的模型合并?

时间:2018-02-18 13:11:49

标签: cakephp cakephp-3.0 cakephp-3.x cakephp-3.4

我是CakePHP的初学者,我使用的是3.5版本。我真的很困惑。我的问题是我想从两个不同的模型中合并两个表单。在我的例子中,我想在一个表单中合并客户端事务添加表单和服务详细信息添加表单。以下是我的代码:

add.ctp(我在服务详细信息添加表单中合并了添加客户端事务表单)

<div class="serviceDetail form large-9 medium-8 columns content">
<?= $this->Form->create($clientTransaction) ?>
<fieldset>
    <legend><?= __('Add Client Transaction') ?></legend>
    <?php
        echo $this->Form->control($serviceDetail->client_transaction->client->id, ['options' => $clients]);
        echo $this->Form->control($serviceDetail->client_transaction->client->transaction_date, ['timeFormat' => 12, 'disabled' => false]);
        echo $this->Form->control($serviceDetail->client_transaction->client->status, ['type' => 'hidden', 'value' => 0]);
    ?>
</fieldset>
<?= $this->Form->create($serviceDetail) ?>
<fieldset>
    <legend><?= __('Add Service Detail') ?></legend>
    <?php
        echo $this->Form->control('service_id', ['options' => $service,  'empty' => true]);
        echo $this->Form->control('user_id', ['options' => $users, 'empty' => true, 'label'=> ['text' => 'Barber']]);
        echo $this->Form->control('client_transaction_id', ['options' => $clientTransaction, 'empty' => true]);
    ?>
</fieldset>
<?= $this->Form->button(__('Submit')) ?>
<?= $this->Form->end() ?>

在我的service_detail控制器

public function add()
{
    $this->paginate = [
        'contain' => ['Service', 'Users', 'ClientTransaction']
    ];
    $clientTransaction = $this->ServiceDetail->ClientTransaction->newEntity();
    $serviceDetail = $this->ServiceDetail->newEntity();
    if ($this->request->is('post')) {
        $clientTransaction = $this->ServiceDetail->ClientTransaction->patchEntity($clientTransaction, $this->request->getData());
        $serviceDetail = $this->ServiceDetail->patchEntity($serviceDetail, $this->request->getData());
        if ($this->ServiceDetail->ClientTransaction->save($clientTransaction) && $this->ServiceDetail->save($serviceDetail)) {
            $this->Flash->success(__('The transaction has been added.'));

            return $this->redirect(['action' => 'add']);
        }
        $this->Flash->error(__('Please, try again.'));
    }
    $service = $this->ServiceDetail->Service->find('list', ['limit' => 200]);
    $users = $this->ServiceDetail->Users->find('list',['limit' => 200, 'valueField' => 'first_name'])->where(['position' => 2]);
    $clientTransaction = $this->ServiceDetail->ClientTransaction->find('list', ['limit' => 200]);
    $clients = $this->ServiceDetail->ClientTransaction->Clients->find('list', ['limit' => 200]);
    $serviceDetail = $this->paginate($this->ServiceDetail);
    $this->set(compact('serviceDetail', 'service', 'users', 'clientTransaction'));
}

1 个答案:

答案 0 :(得分:0)

做这样的事情:

$serviceDetail = $this->ServiceDetail->newEntity(
    $this->request->getData(), [
        'associated' => ['ClientTransaction']
    ]
);

https://book.cakephp.org/3.0/en/orm/saving-data.html#converting-request-data-into-entities

对于您的页面,请遵循以下模式: https://book.cakephp.org/3.0/en/views/helpers/form.html#creating-inputs-for-associated-data