Code Description Whatever
---------------------------------
1 stuff blah
1 something meh
2 yah bong
2 never hammer time
如何从每个Code
出现一次,从而获得结果集? (我并不过分关心该代码的记录)。
所以我想......
1 stuff blah
2 yah bong
答案 0 :(得分:0)
SELECT *
FROM (
SELECT * , row_number() over(partition by code order by Description) as id
from yourTable
) temp
WHERE id = 1
我认为这只是sql server
答案 1 :(得分:0)
首先需要选择一个确定“第一个结果”的列。在我的示例中,我选择了Description
:
SELECT * FROM YourTable first
WHERE
(SELECT COUNT(*) FROM YourTable previous
WHERE previous.Code=first.Code AND previous.Description < first.Description) = 0