Question

我刚开始写java并且有一个问题我必须完成大学学业。到目前为止，我已经完成了问题要求我做的所有事情，除了我必须输入名称的最后一部分，如果名称与字符串数组中的名称相匹配，它将计算值。现在卡住它2小时，请帮忙

      System.out.println();
  System.out.print("Enter the candidate's name: ");
  candi[0] = keyIn.nextLine();


  for(int i = 0; i<votes.length; i++)
  {
     if(candi[0].equals(names[i]))
     {

        for(int h = 0; h<votes.length; h++)
           {

              if(votes[i] == votes[h])
              {
                 same = same+1;
              }
              else if(votes[i]<votes[h])
              {
                 less = less+1;
              }
              else if(votes[i]>votes[h])
              {
                 more = more + 1;
              }
           }
     }
     else
     {

           System.out.print("Name does not match, enter again : ");
           candi[0] = keyIn.nextLine();
     }
  }

Answer 1

您的问题是您只检查每个输入的一个名称（i处的名称）。您需要遍历所有名称以检查输入的名称是否与数组中的一个匹配。为了解决这个问题，我将整个事情包装在一个while循环中，并将匹配检查分离到它自己的小for循环：

    String[] names = {"Dunne","Doherty","McGlynn","Grant","Sweeney","McHugh","Gibbons","O'Neill"}; 
    int[] votes = {0,13,28,6,6,29,15,5}; 
    double[] avg = {0.0,12.7,27.5,5.9,5.9,28.4,14.7,4.9};

    System.out.println();
    System.out.print("Enter the candidate's name: ");
    Scanner scan = new Scanner(System.in);
    String in = scan.nextLine();

    boolean containsName = false;

    while (true) { // continue asking for names until one mathces

        // Check if name is present
        for(int i = 0; i<names.length; i++)
        {
            if(in.equals(names[i]))
            {
                containsName = true;
                break; // break the for loop
            }
        }

        // do something if name is present, continue if not
        if(containsName) {
            System.out.println("Calc!");
            break; // break the while loop
        }else {
            System.out.print("Name does not match, enter again : ");
            in= scan.nextLine();
        }


    }

Answer 2

我猜您正在寻找类似的内容：

您可以在找到用户输入的名称时执行某些操作在候选人名单中。

工作代码：

import java.util.Scanner;

class match {
    match() {
        Scanner keyIn = new Scanner(System.in); //for taking input
        String candi[] = new String[1];         //for storing name input
        String candiNames[] = { "ab", "bc", "cd" }; //String array of candidate names
        Boolean found = false; //flag to check if name found or not

        System.out.print("Enter the candidate's name: ");
        candi[0] = keyIn.nextLine(); //taking input

        for (String n : candiNames) { //looping 
            if (candi[0].equalsIgnoreCase(n)) { //matching string (ignoreing case)

                found = true;
                // do the working here for anything you wish to do on match
                // found
            }

        }
        if (found == true) {
            System.out.println("Match found ");

        } else if (found == false) {
            System.out.println("Match not found for : " + candi[0]);
        }
    }

}

public class StringName {
    public static void main(String args[]) {
        new match();
    }
}

输出：

找到匹配

未找到匹配

我希望我帮助过。）

在一个字符串数组中搜索另一个

2 个答案: