我的代码有问题：错误＆＃34;没有类型＆＃34;

Question

1. 函数接受两个函数f和g，并找到a和b之间的交点与eps的容差，换句话说，找到点c使得f（c）的绝对值 - g（c）

2. 上面的问题是我得到的＆＃34;没有＆＃34;作为我的输出

   #defining two functions
   
   f1 = lambda x: 2*x + 3
   g1 = lambda x: 3*x - 4
   
   # making a function called "intersect"
   # a and b is the upper and lower limit
   # eps is the tolerance of the answer
   def intersect(f,g,a,b,eps):
       c1= 0                   #defining c1 (real number) for simplicity                   
       n = 1                   # to limit the number of iteration
      while n <= 1000:
          c1 = (a+b)/2        #using bisection formula
          if abs(f(c1) - g(c1)) < eps or ((b-a)/2)<eps:       # two conditions |f(c)-g(c)| <eps
              break
              return c1
          if f(c1)<=0:        # accd to bisection theorem
              a = c1
          else:
              b = c1         # accd to bisection theorem
          n +=1              # incrementing to limit the iteration
   print(intersect(f1,g1, -10, 10, 0.001))
   

Answer 1

问题在于：

   if abs(f(c1)-g(c1)) < eps or ((b-a)/2) < eps:
       break
       return c1

break语句在返回值之前退出while循环，并且由于没有返回其他值，函数的返回值为None。
返回值后，函数退出，因此您不需要break语句。