有没有办法在调用方法中获取变量/参数的原始名称,因为它已被命名?
在某种程度上,它类似于[CallerMemberName]
属性,但对于变量/参数。
更新2018.02:此问题类似于以下问题:1,2和3,但仍然无效,标准化解决方案在2018年初。
建议的解决方案:使用Expression<Func<T>>
可以拥有 non-documented effects 并且非常 CPU密集型,因为将代码转换为表达式以获取原始名称变量只是一个简单的动作。
这就像创建一个1М大小的空数组来存储单个整数而不是简单的整数 - 非常无效(«згарматипогоробцям»)。
简短示例:
int ComplexMathMethod(int startPos, int endPos,
int backgroundStartPos, int backgroundEndStart,
int squareStartPos, // …and other positions… )
{
CheckPosition(startPos);
CheckPosition(endPos);
CheckPosition(backgroundStartPos);
CheckPosition(backgroundEndStart);
CheckPosition(squareStartPos);
// …and so on…
}
void CheckPosition(int position)
{
bool isValidPosition = // complex check;
if (!isValidPosition)
{
throw new ArgumentException(nameof(position));
// --->>> It will be extremely convenient to automatically replace "nameof(position)" with original
// name of variable/argument from caller method, like: "startPos", "endPos", "backgroundStartPos", etc.
// Additional string argument with original variable name is not a good solution too.
// Because, I have similar "check" method that checks 4 connected position’s integers at once.
// Therefore, 4 input ints with additional +4 string arguments will make a mess.
}
}
长例:
void ShowMessage(string messageStr)
{
// Problem: get original variable/argument name, as it was called, in the caller method.
string callerMethodArgName;
// If method was called from "Main" method, than callerMethodArgName should equal to "finishMsg".
// If method was called from "DoWork" method, than callerMethodArgName should equal to "taskName".
// If method was called from "StartProgram" method, than callerMethodArgName should equal to "startingMsg".
// …missing logic, reflection code, etc.
// The next line is just a stub.
callerMethodArgName = nameof(messageStr);
Console.WriteLine($"Variable name is \"{callerMethodArgName}\"; value is \"{messageStr}\".");
}
void Main()
{
StartProgram();
DoWork("Programming…");
// Example 1.
string finishMsg = "Finish!";
ShowMessage(finishMsg);
}
// Example, caller method 2.
void StartProgram()
{
string startingMsg = "Starting program";
ShowMessage(startingMsg);
}
// Example, caller method 3.
void DoWork(string taskName)
{
ShowMessage(taskName);
}
当前节目输出:
// Variable name is "messageStr"; value is "Starting program".
// Variable name is "messageStr"; value is "Programming…".
// Variable name is "messageStr"; value is "Finish!".
必需/所需的输出:
// Variable name is "startingMsg"; value is "Starting program".
// Variable name is "taskName"; value is "Programming…".
// Variable name is "finishMsg"; value is "Finish!".
我不确定这是否可行。我花了几个小时玩反射,但不幸的是,它没有结果。在实际项目中进行调试时,这将非常方便。
答案 0 :(得分:3)
您可以使用Linq.Expressions。首先,您需要更改--name-status
的签名,如下所示:
--name-only
之后你可以这样称呼它:
CheckPosition
完整代码:
void CheckPosition(Expression<Func<int>> positionExpression)