Question

目前，这是我的代码，但它不起作用：

//$queryBalance is the array received from an sql select
foreach ($queryBalance as $index => $runrows){ 
    $val = $runrows->balance;
    $val = str_ireplace(".","",$val);
    $val = str_ireplace(",",".",$val);
    //echo($i.' - '.$runrows->id_month.' ; ');
    //$valor = $runrows->id_month == $i ? $val : 'Null';
    if($i > $monthFim){
        $i = $monthInicio-1;
        array_push($balanceArray, $balanceTeste);                     
        echo('('.$i.' - '.$runrows->id_month.'); ');
        //dd('('.$balanceArray.' - '.$balanceTeste.'); ');
    }else{
        array_push($balanceTeste, $valor);
    }
    $i++; 
}

我想转换这个输入数组（$queryBalance）：

array:6 [
   0 => {
    "balance": "-257,21"
    "id_month": 1
    "year": "2018"
  }
  1 => {
    "balance": "-257,21"
    "id_month": 2
    "year": "2018"
  }
  2 => {
    "balance": "0"
    "id_month": 1
    "year": "2018"
  }
  3 => {
    "balance": "0"
    "id_month": 2
    "year": "2018"
  }
  4 => {
    "balance": "-64609,14"
    "id_month": 1
    "year": "2018"
  }
  5 => {
    "balance": "-64609,14"
    "id_month": 2
    "year": "2018"
  }
]

进入此（索引名称无关紧要，我把它放在那里以举例说明逻辑）：

array:3 [
   0 => {
    "balance_month1_year2018": "-257,21"
    "balance_month2_year2018": "-257,21"
  }
  1 => {
    "balance_month1_year2018": "0"
    "balance_month2_year2018": "0"
  }
  2 => {
    "balance_month1_year2018": "-64609,14"
    "balance_month2_year2018": "-64609,14"
  }
]

基本上，我希望按年和月分组以获得余额。

ps：将始终订购数据

Answer 1

生成一系列独特的年份和月份组合。
（*声明为关键以确保它们是唯一的。）
迭代$queryBalance，直到空/耗尽。
（*如果您需要重复使用原始$queryBalance制作副本。）
将$queryBalance的第一个子数组指定为下一行的变量。
如果$uniques的预期日期对与$first日期对相同，请删除第一个子阵列（通过array_shift()）并存储余额;否则存储NULL，不要修改$queryBalance。
$temp是一个＆＃34;批处理＆＃34;阵列。完成foreach循环后，批处理已准备好转移到$result。

代码：（Demo）

$queryBalance=[
    (object)["balance"=>"-257,21","id_month"=>12,"year"=>"2017"],
    (object)["balance"=>"-257,21","id_month"=>1,"year"=>"2018"],
    (object)["balance"=>"-257,21","id_month"=>2,"year"=>"2018"],
    (object)["balance"=>"166,66","id_month"=>3,"year"=>"2018"],
    (object)["balance"=>"55","id_month"=>12,"year"=>"2017"],
    //(object)["balance"=>"0","id_month"=>1,"year"=>"2018"],
    (object)["balance"=>"0","id_month"=>2,"year"=>"2018"],
    (object)["balance"=>"55","id_month"=>3,"year"=>"2018"],
    (object)["balance"=>"-22257,21","id_month"=>12,"year"=>"2017"],
    (object)["balance"=>"-64609,14","id_month"=>1,"year"=>"2018"],
    (object)["balance"=>"-64609,14","id_month"=>2,"year"=>"2018"],
    (object)["balance"=>"-12234,89","id_month"=>3,"year"=>"2018"]
];
foreach($queryBalance as $row){
    $uniques[$row->year.'-'.$row->id_month]=NULL;  // determine all unique date groups
}

while($queryBalance){
    $temp=[];
    foreach($uniques as $date=>$null){
        $first=current($queryBalance);  // cache the element that is currently first in $queryBalance
        $temp[]=($date==$first->year.'-'.$first->id_month) ? array_shift($queryBalance)->balance : NULL;  // extract from array, or store NULL without modifying $queryBalance
    }
    $result[]=$temp;
}

var_export($result);

输出：

array (
  0 => 
  array (
    0 => '-257,21',
    1 => '-257,21',
    2 => '-257,21',
    3 => '166,66',
  ),
  1 => 
  array (
    0 => '55',
    1 => NULL,
    2 => '0',
    3 => '55',
  ),
  2 => 
  array (
    0 => '-22257,21',
    1 => '-64609,14',
    2 => '-64609,14',
    3 => '-12234,89',
  ),
)

将数组中的值转换为另一个多维数组

1 个答案: