Question

我希望获得过去3个工作日内发生的任何数据如果今天是星期一，我希望我的查询提取上周三，周四和周五发生的数据如果是星期二，请提取周四，周五和周一发生的数据。如果是星期三，请在周五，周一，周二拉。等

这是我在WHERE语句中到目前为止所做的，但我知道这是不正确的。

AND CASE
WHEN DATENAME(DW, GETDATE()) = 'Monday' THEN CAST(PE.SchedDt AS DATE) BETWEEN DATEADD(DAY,-5,CAST(GETDATE()AS DATE)) AND DATEADD(DAY,-3,CAST(GETDATE()AS DATE))
WHEN DATENAME(DW, GETDATE()) = 'Tuesday' THEN CAST(PE.SchedDt AS DATE) BETWEEN DATEADD(DAY,-5,CAST(GETDATE()AS DATE)) AND DATEADD(DAY,-1,CAST(GETDATE()AS DATE))
WHEN DATENAME(DW, GETDATE()) = 'Wednesday' THEN CAST(PE.SchedDt AS DATE) BETWEEN DATEADD(DAY,-5,CAST(GETDATE()AS DATE)) AND DATEADD(DAY,-2,CAST(GETDATE()AS DATE))
ELSE CAST(PE.SchedDt AS DATE) BETWEEN DATEADD(DAY,-3,CAST(GETDATE()AS DATE)) AND DATEADD(DAY,-1,CAST(GETDATE()AS DATE))
END

非常感谢任何帮助！

Answer 1

您可以使用WEEKDAY（）函数将工作日分配给每个日期。然后你必须比较你当前的工作日WEEKDAY（CURDATE（））是否在3的范围内。

        CREATE TABLE data_table (date_column DATE, some_data VARCHAR(1));

        INSERT INTO data_table 
        VALUES ('2018-02-12', 'b'),('2018-02-14', 'a'),('2018-02-13', 'c'),
    ('2018-02-15', 'b'),('2018-02-16', 'a'),('2018-02-15', 'd'),
    ('2018-02-11', 'a'),('2018-02-10', 'e');

        SELECT * 
        FROM (
        SELECT a.*,WEEKDAY(date_column) weekday, WEEKDAY(CURDATE()) current_day 
        FROM data_table a
        ) b 
        WHERE 
        (b.weekday in (2,3,4) and current_day = 0)
        or (b.weekday in (3,4,0) and current_day = 1)
        or (b.weekday in (4,0,1) and current_day = 2)
        or (b.weekday < current_day && b.weekday >= current_day - 3);

抓取过去3个工作日的数据

1 个答案: