抛出了描述“资源暂时不可用”的C ++异步异常

Question

我在Ubuntu 16.04中创建线程并检索数据如下所示

     vector<std::future<TestResult>> futureVector;
     for(int i = 0; i < number_of_threads; i ++) {
         auto future = std::async(
            std::launch::async,
            &testFunction,
            this,
            parameter);
         futureVector.push_back(move(future));
     }


     for (int i = 0; i < futureVector.size(); i++)
     {
       auto result = futureVector[i].get();
     }

但它会抛出

  

描述“资源暂时不可用

的异常

我认为这可能是因为我创建了太多超出操作系统限制的线程。如果任何人都可以提供调试方法，那将非常有用。

编辑：

ulimit的结果-a

core file size          (blocks, -c) 0
data seg size           (kbytes, -d) unlimited
scheduling priority             (-e) 0
file size               (blocks, -f) unlimited
pending signals                 (-i) 983354
max locked memory       (kbytes, -l) 64
max memory size         (kbytes, -m) unlimited
open files                      (-n) 1024
pipe size            (512 bytes, -p) 8
POSIX message queues     (bytes, -q) 819200
real-time priority              (-r) 0
stack size              (kbytes, -s) 8192
cpu time               (seconds, -t) unlimited
max user processes              (-u) 983354
virtual memory          (kbytes, -v) unlimited
file locks                      (-x) unlimited