由于标题建议我想循环现有的字典并更改一些值,根据这个question的答案,我提出了下面的代码,但它不起作用,因为值是在第二次调试调用中没有改变,我认为这是因为在另一个问题中他们是从头开始创建一个新的字典,但是我也尝试过没有外部花括号,我本以为会有导致它改变现有价值。
- set_fact:
uber_dict:
a_dict:
some_key: "abc"
another_key: "def"
b_dict:
some_key: "123"
another_key: "456"
- debug: var="uber_dict"
- set_fact: "{ uber_dict['{{ item }}']['some_key'] : 'xyz' }"
with_items: "{{ uber_dict }}"
- debug: var="uber_dict"
答案 0 :(得分:5)
您无法更改现有变量,但您可以注册同名的新变量。
检查此示例:
---
- hosts: localhost
gather_facts: no
vars:
uber_dict:
a_dict:
some_key: "abc"
another_key: "def"
b_dict:
some_key: "123"
another_key: "456"
tasks:
- set_fact:
uber_dict: "{{ uber_dict | combine(new_item, recursive=true) }}"
vars:
new_item: "{ '{{ item.key }}': { 'some_key': 'some_value' } }"
with_dict: "{{ uber_dict }}"
- debug:
msg: "{{ uber_dict }}"
结果:
ok: [localhost] => {
"msg": {
"a_dict": {
"another_key": "def",
"some_key": "some_value"
},
"b_dict": {
"another_key": "456",
"some_key": "some_value"
}
}
}