Question

任务是在json中序列化类并将其传递给服务器上的POST。我写了代码并且它有效，但我感觉我做了很多不必要的事情。及时的良好实践来解决我的问题。

//package - a serializable object that must be passed
JsonPackage package = new JsonPackage( userData ); 
DataContractJsonSerializer jsonFormatter = new DataContractJsonSerializer( typeof( JsonPackage ) );

WebRequest request = WebRequest.Create( "http://localhost:52733/set" );
request.ContentType = "application/json";
request.Method = "POST";

MemoryStream ms = new MemoryStream();

jsonFormatter.WriteObject( ms, package );

ms.Flush();
ms.Position = 0;

StreamReader sr = new StreamReader( ms );
string jsonString = sr.ReadToEnd();

StreamWriter sw = new StreamWriter( request.GetRequestStream() );
sw.Write( jsonString );

sr.Dispose();
sw.Dispose();
ms.Dispose();
request.GetResponse();

更新感谢所有的答案，你帮助我学到了很多东西。我接受了另一个建议并写了如下：

//package - a serializable object that must be passed
JsonPackage package = new JsonPackage( Data );
DataContractJsonSerializer jsonFormatter = new DataContractJsonSerializer( typeof( JsonPackage ) );

WebRequest request = WebRequest.Create( "http://localhost:52733/set" );
request.ContentType = "application/json";
request.Method = "POST";

using ( var stream = request.GetRequestStream() )
{
    jsonFormatter.WriteObject( stream, package );
}
request.GetResponse();

告诉我我的决定存在缺陷吗？

Answer 1

如果您使用NewtonSoft.Json，序列化步骤将是一个简单的JsonConvert.SerializeObject(<<object>>)。希望这会有所帮助。\

以下是您的代码的简化版本。

            var client = new System.Net.Http.HttpClient();

            var content = new     StringContent(JsonConvert.SerializeObject(data));
            client.BaseAddress = new Uri("http://localhost:52733/");
            client.DefaultRequestHeaders.Accept.Add(new System.Net.Http.Headers.MediaTypeWithQualityHeaderValue("application/json"));
            var response = client.PostAsync("set", content).Result;
            //do what ever you want to do with response

Answer 2

您确实可以使用HttpClient及其PostAsJsonAsync方法减少行数。由于该方法是异步的，并且我假设您的代码可能不是的方法，您将需要访问PostAsJsonAsync的awaiter来获取请求的结果。

var client = new HttpClient();

// response is an HttpResponseMessage instance
var response = client.PostAsJsonAsync("http://localhost:52733/set", userData)
                     .GetAwaiter().GetResult();

您还可以在那里获得有关HttpClient用法的更多详细信息：https://docs.microsoft.com/en-us/aspnet/web-api/overview/advanced/calling-a-web-api-from-a-net-client

Answer 3

我希望我能提供帮助。我用restSharp。要使用它，您需要安装RestSharp

http://restsharp.org/ https://www.nuget.org/packages/RestSharp/106.3.0-alpha0002

和NewtonSoft.Json。

https://www.nuget.org/packages/newtonsoft.json/

private bool Post(<<DataStaructure>> inputParam)
    {
        var jsonSerializerSettings =
            new JsonSerializerSettings { ContractResolver = new CamelCasePropertyNamesContractResolver() };

        var client = new RestClient("http://localhost:52733/set/");
        var request = new RestRequest(Method.POST);
        var jsonToSend = JsonConvert.SerializeObject(inputParam, jsonSerializerSettings);
        request.AddParameter("application/json; charset=utf-8", jsonToSend, ParameterType.RequestBody);
        IRestResponse response = client.Execute(request);

        if (response.IsSuccessful == false)
        {
            throw new Exception(response.ErrorMessage);
        }
        else
        {
            return Convert.ToBoolean(response.Content);

        }
    }

使用POST方法从{C}应用程序发送数据

3 个答案: