Question

我必须构建一个接受数组和字符串的方法。该方法应该返回一个包含三个元素的数组。它在索引0处的元素应该是字符串参数，并且它不应该包含数组参数的最后一个元素。

对于数组：

best_teams = ([Boston Celtics, LA Lakers, Chicago Bulls]

和字符串：

my_team = ("Utah Jazz")

我期待输出：

[Utah Jazz, Boston Celtics, LA Lakers]

我试过了：

def teams(best_teams, my_team)
  sec = my_team.split + best_teams
  return sec - sec[3].split
end

但它似乎不起作用。有什么想法吗？

Answer 1

看，假设以下值：

best_teams = ['Boston Celtics', 'LA Lakers', 'Chicago Bulls']
my_team = "Utah Jazz"

def teams(best_teams, my_team)
  # sec = nil
  sec = my_team.split + best_teams
  # the values at this point are
  # sec = ["Utah", "Jazz"] + ['Boston Celtics', 'LA Lakers', 'Chicago Bulls']
  # your single team name now become in an array with two values 
  # finally
  # sec = ["Utah", "Jazz", 'Boston Celtics', 'LA Lakers', 'Chicago Bulls']
  return sec - sec[3].split
  # ["Utah", "Jazz", 'Boston Celtics', 'LA Lakers', 'Chicago Bulls'] - ["LA", "Lakers"]
  # ["Utah", "Jazz", "Boston Celtics", "LA Lakers", "Chicago Bulls"]
end

请检查 https://apidock.com/ruby/String/split。真正的问题是我猜你不知道如何拆分工作

获取字符串和数组并返回修改后的合并数组

1 个答案: