Question

我的while循环遇到了麻烦。在第三次执行后，它不会接受用户输入它只输出＆＃34;输入你的名字＆＃34;。我尝试了很多东西，但它们似乎并没有起作用。循环应该继续运行，直到用户输入＆＃34;否＆＃34;。

我知道我已经关闭了！

System.out.print("Would you like to enter another patient? Type Yes or No: ");
String userInput = input.nextLine();
if (userInput.equals("Yes")) 
{
    while (userInput.equals("Yes")) 
    {
        System.out.print("Enter your first name: ");
        String firstName2 = input.nextLine();
        System.out.print("Enter your last name: ");
        String lastName2 = input.nextLine();
        System.out.print("Enter your address: ");
        String address2 = input.nextLine();
        System.out.print("Enter your city: ");
        String city2 = input.nextLine();
        System.out.print("Enter your state: ");
        String state2 = input.nextLine();
        System.out.print("Enter your zip code + 4: ");
        String zip2 = input.nextLine();
        System.out.print("Enter amount owed: ");
        String amount2 = input.nextLine();
        System.out.print("Enter your payment amount: ");
        String payment2 = input.nextLine();
        System.out.print("Enter the date of payment: ");
        String date2 = input.nextLine();
        System.out.println("\t\t\t\t\t" + "XYZ Hospital");
        System.out.println();
        System.out.println("Name Information" + "\t\t\t\t" + "Address" + "\t\t\t\t\t\t" + "Payment");
        System.out.println();
        System.out.println("Last" + "\t" + "First" + "\t\t\t" + "Address Line 1" + "\t" + "City" + "\t" + "State" + "\t" + "Zip" + "\t" + "Amount Owed" + "\t" + "Payment Amount" + "\t" + "Payment Date");
        System.out.println();
        System.out.println(lastName2 + " " + firstName2 + "\t" + address2 + " " + city2 + ", " + state2 + " " + zip2 + "\t" + amount2 + "\t\t" + payment2 + "\t\t" + date2);
        System.out.print("Would you like to enter another patient? Type Yes or No: ");
    }
}
else if (userInput.equals("No")) 
{
    System.out.println("Goodbye");
}

Answer 1

对于这些类型的程序，您可以使用do-while循环。这是第一次没有条件运行，然后你可以在userInput变量中获得用户的输入。

.text-div {
    position: relative;
    top: 50%;
    transform: translateY(-50%);
    display: table;
 }

Answer 2

我认为问题是你在if语句中做了while循环。尝试在循环中插入if，如下所示：

    Scanner input=new Scanner(System.in);
    System.out.println("enter details");
    String answer=input.next();
    while(answer.equals("yes")) {
        if(answer.equals("yes")) {
System.out.println("name");
String name=input.next();
System.out.println("last name");
String last=input.next();
System.out.println("enter details");
     answer=input.next();    
} }

System.out.println("bye");

    }

Answer 3

你永远不会离开你的循环，因为userInput只在循环之前设置一次并且永远不会在其中设置，这意味着你永远不会改变while条件。

System.out.print("Would you like to enter another patient? Type Yes or No: ");
String userInput = input.nextLine();
if (userInput.equals("Yes")) {
    while (userInput.equals("Yes")) {
        //your data entry...

        System.out.print("Would you like to enter another patient? Type Yes or No: ");
        // change userInput here, else, you're never going out of the loop.
        // so add this
        userInput = input.nextLine();
    }
} else if (userInput.equals("No")) {
    System.out.println("Goodbye");
}

尽管如此，您的解决方案可能会更符合您的需求：

System.out.print("Would you like to enter another patient? Type Yes or No: ");
String userInput = input.nextLine();
while (userInput.equals("Yes")) {
    //your data entry...

    System.out.print("Would you like to enter another patient? Type Yes or No: ");
    userInput = input.nextLine();
}

System.out.println("Goodbye");

这样，而用户输入＆＃34;是＆＃34;，当他输入其他内容时，您将进入循环并离开。如果用户输入的内容不是＆＃34;是＆＃34;从一开始，你就永远不会进入循环并立即关闭应用程序。

Answer 4

工作代码：请检查代码

import java.util.Scanner;

public class temp {
    static String userInput;
    private static Scanner input;

    public static void main(String[] args) {
        input = new Scanner(System.in); 

        System.out
                .print("Would you like to enter another patient? Type Yes or No:  ");
        userInput = input.nextLine();

        while (userInput.equals("Yes")) { //while loop will iterate till "userInput is equals to Yes"
            System.out.print("Enter your first name: ");
            String firstName2 = input.nextLine();
            System.out.print("Enter your last name: ");
            String lastName2 = input.nextLine();
            System.out.print("Enter your address: ");
            String address2 = input.nextLine();
            System.out.print("Enter your city: ");
            String city2 = input.nextLine();
            System.out.print("Enter your state: ");
            String state2 = input.nextLine();
            System.out.print("Enter your zip code + 4: ");
            String zip2 = input.nextLine();
            System.out.print("Enter amount owed: ");
            String amount2 = input.nextLine();
            System.out.print("Enter your payment amount: ");
            String payment2 = input.nextLine();
            System.out.print("Enter the date of payment: ");
            String date2 = input.nextLine();
            System.out.println("\t\t\t\t\t" + "XYZ Hospital");
            System.out.println();
            System.out.println("Name Information" + "\t\t\t\t" + "Address"
                    + "\t\t\t\t\t\t" + "Payment");
            System.out.println();
            System.out.println("Last" + "\t" + "First" + "\t\t\t"
                    + "Address Line 1" + "\t" + "City" + "\t" + "State" + "\t"
                    + "Zip" + "\t" + "Amount Owed" + "\t" + "Payment Amount"
                    + "\t" + "Payment Date");
            System.out.println();
            System.out.println(lastName2 + " " + firstName2 + "\t" + address2
                    + " " + city2 + ", " + state2 + " " + zip2 + "\t" + amount2
                    + "\t\t" + payment2 + "\t\t" + date2);
            System.out
                    .print("Would you like to enter another patient? Type Yes or No: \n");
            userInput = input.nextLine(); // Taking user choice for "Yes" or "No"

            if (userInput.equals("No")) {
                break; // will Exit loop when user enter "No"
            }
        }

        if (userInput.equals("No")) {
            System.out.println("Goodbye");
        } else {
            System.out.println(" Invalid input :("); // will print when user enter anything other than "Yes" or "No"

        }
    }
}

完成后，您没有再次收到用户的输入从while循环中的用户获取数据。还要检查代码评论更多信息。

Answer 5

最重要的问题是，在第一次检查后，您永远不会更改userInput的值。所以无论他们是否输入＆＃34;是＆＃34;或＆＃34;否＆＃34;在循环结束时，它将保持循环。当您询问是否要进入另一位患者时，您甚至不会让用户选择在循环结束时输入任何内容。其次你应该检查他们是否输入了'是，是，是，是＆＃34;使用a降低功能

而Java中的循环问题

5 个答案: