我们都知道these excellent ABAP statements允许在单行中找到唯一值:
it_unique = VALUE #( FOR GROUPS value OF <line> IN it_itab
GROUP BY <line>-field WITHOUT MEMBERS ( value ) ).
但是提取重复项呢?可以使用GROUP BY
语法来完成该任务,或者,表格理解在这里更有用吗?
我找到的唯一(虽然不是很优雅)方式是:
LOOP AT lt_marc ASSIGNING FIELD-SYMBOL(<fs_marc>) GROUP BY ( matnr = <fs_marc>-matnr
werks = <fs_marc>-werks )
ASSIGNING FIELD-SYMBOL(<group>).
members = VALUE #( FOR m IN GROUP <group> ( m ) ).
IF lines( members ) > 1.
"throw error
ENDIF.
ENDLOOP.
是否有通过任意键查找重复项的更美妙方法?
答案 0 :(得分:1)
鉴于
TYPES: BEGIN OF key_row_type,
matnr TYPE matnr,
werks TYPE werks_d,
END OF key_row_type.
TYPES key_table_type TYPE
STANDARD TABLE OF key_row_type
WITH DEFAULT KEY.
TYPES: BEGIN OF group_row_type,
matnr TYPE matnr,
werks TYPE werks_d,
size TYPE i,
END OF group_row_type.
TYPES group_table_type TYPE
STANDARD TABLE OF group_row_type
WITH DEFAULT KEY.
TYPES tt_materials TYPE STANDARD TABLE OF marc WITH DEFAULT KEY.
DATA(materials) = VALUE tt_materials(
( matnr = '23' werks = 'US' maabc = 'B' )
( matnr = '42' werks = 'DE' maabc = 'A' )
( matnr = '42' werks = 'DE' maabc = 'B' ) ).
当
DATA(duplicates) =
VALUE key_table_type(
FOR key IN VALUE group_table_type(
FOR GROUPS group OF material IN materials
GROUP BY ( matnr = material-matnr
werks = material-werks
size = GROUP SIZE )
WITHOUT MEMBERS ( group ) )
WHERE ( size > 1 )
( matnr = key-matnr
werks = key-werks ) ).
然后
cl_abap_unit_assert=>assert_equals(
act = duplicates
exp = VALUE tt_materials( ( matnr = '42' werks = 'DE') ) ).
此解决方案的可读性非常糟糕,您只能在具有明显名称collect_duplicate_keys
的方法中使用它。
另请注意,语句的长度随着关键字段数量的增加而增加,因为GROUP SIZE
添加要求将关键字段逐个列为简单类型列表。
答案 1 :(得分:1)
所以,我只是把它作为答案,因为我们和Florian没有能够更好地思考一些事情。
如果有人能够改进它,那就去做吧。
TYPES tt_materials TYPE STANDARD TABLE OF marc WITH DEFAULT KEY.
DATA duplicates TYPE tt_materials.
LOOP AT materials INTO DATA(material)
GROUP BY ( id = material-matnr
status = material-pstat
size = GROUP SIZE )
ASCENDING REFERENCE INTO DATA(group_ref).
CHECK group_ref->*-size > 1.
duplicates = VALUE tt_materials( BASE duplicates FOR <status> IN GROUP group_ref ( <status> ) ).
ENDLOOP.
答案 2 :(得分:0)
经典怎么样?我不确定它们是否已被弃用,但我的第一个想法是创建一个表克隆,DELETE ADJACENT-DUPLICATES,然后只比较两行()... 我会急于阅读新的选项。