Question

我收到此错误：

解析错误：语法错误，意外＆＃39;＆gt;＆＃39;在第40行的C：\ xampp \ htdocs \ jagan \ display.php

这是我的代码：

<html>
<head><title> Display Student Results </title></head>
<body>
<form action="display.php method="post">
<table>
<tr>
<td>Enter Hallticket Number:
<td><input type="number" name="hno">
</tr>
<tr>
<td><input type="submit" name="btnsearch" value="search">
</tr>
</table>
</form>
</body>
</html>

<?php
$conn=mysqli_connect("localhost","root","")or die("unable to connect");
mysqli_select_db($conn,"college");

if(isset($_POST['btnsearch']))
{
$hall=$_POST['hno'];
$result=mysqli_connect($conn,"select * from student where hno=$hall");
echo "<h1> Student Results </h1>";
echo "<table border=5>";
echo "<tr>";
echo "<th> hallticket";
echo "<th> Name";
echo "<th> class";
echo "<th> gst";
echo "<th> Tax";
echo "<th> php";
echo "<th> dmdw";
echo "<th> accounts";
echo "</tr>;
while($rows=mysqli_fetch_assoc($result))
{
echo "<tr>";
echo "<td>".rows['hno'];
echo "<td>".rows['name'];
echo "<td>".rows['class'];
echo "<td>".rows['gst'];
echo "<td>".rows['tax'];
echo "<td>".rows['php'];
echo "<td>".rows['dmdw'];
echo "<td>".rows['acc'];
echo "</tr>";
}
echo "</table>";
}
?>

Answer 1

你没有正确地调用mysql结果集，它＆＃34; row＆＃34;不是＆＃34;行＆＃34;。 Here are the docs

echo "<td>".rows['hno'];

应该是：

echo "<td>".row['hno'];

此外，您的HTML表格未正确形成。请查看this resource以了解如何创建表格。

您需要关闭<th>和<td>标签，如下所示：

echo "<th>Name</th>";

这是一个great tutorial，它将引导您完成PHP / MySQL编码。通过第一次工作将意味着更少的旅行到SO寻求帮助。

如何修复意外的＆＃39;＆gt;＆＃39;错误？

1 个答案: