Question

您好我有以下Entity with EmbeddedId id（我使用lombok作为getter，setter和构造函数）：

@Embeddable
@NoArgsConstructor
@AllArgsConstructor
public class SignUpIdentity implements Serializable {

    @NotNull
    @Getter @Setter
    @JoinColumn(name="training")
    @ManyToOne
    private Training training;

    @NotNull
    @Getter @Setter
    @JoinColumn(name="user")
    @ManyToOne
    private User user;

}

@Entity
public class SignUp{

    @EmbeddedId
    @Getter
    @Setter
    private SignUpIdentity signUpIdentity;

    @Getter
    private Date date;

    public SignUp () {
        Calendar cal = Calendar.getInstance();
        this.date = cal.getTime();
    }
}

我还有一个Paging and Sorting存储库和一个控制器：

public interface SignUpRepository extends PagingAndSortingRepository<SignUp, SignUpIdentity> {

}


@Controller
@RequestMapping(path="/signUps")
public class SignUpController {
    @Autowired
    SignUpRepository signUpRepository;

 @RequestMapping(method = RequestMethod.POST)
    public @ResponseBody SignUp createOrUpdate(@RequestBody SignUp titemBody) {
        return signUpRepository.save(titemBody);
    }

    @RequestMapping(path="/find", method = RequestMethod.POST)
    public SignUp readById(@RequestBody SignUpIdentity id) {
        return signUpRepository.findOne(id);
    }
}

问题是，我发送POST请求到/ signUps /发现它不会返回任何结果，即使它应该（我已添加注册培训：2和用户：“1234”）。这是我正在提出的要求的主体：

{
   "training": {"id": 2},
   "user": {"phoneNumber": "1234"}
}

这是回复：

{
"timestamp": 1518693385312,
"status": 404,
"error": "Not Found",
"message": "No message available",
"path": "/signUps/find"
}

我缺少什么？

这些是用户和培训实体：

@Entity
public class Training {
    @Id
    @Getter
    @GeneratedValue(strategy= GenerationType.AUTO)
    private Long id;

    @NotNull
    @Getter @Setter
    private String name;

    @NotNull
    @Getter
    private Date dateOfInsert;

    @OneToMany(mappedBy="signUpIdentity.training")
    @JsonIgnore
    @Getter @Setter
    private Set<SignUp> signUp;

    public Training() {
        Calendar cal = Calendar.getInstance();
        dateOfInsert = cal.getTime();
    }

    public Training(long id) {
        Calendar cal = Calendar.getInstance();
        dateOfInsert = cal.getTime();
        this.id = id;
    }
}

@Entity
public class User {

    @Id
    @Getter @Setter
    private String phoneNumber;

    @NotNull
    @Getter @Setter
    private String nameAndSurname;

    @OneToMany(mappedBy="signUpIdentity.user")
    @Getter @Setter
    @JsonIgnore
    private Set<SignUp> signUp;

    public User() {
        Calendar cal = Calendar.getInstance();
        this.date = cal.getTime();
    }
}

我甚至在存储库中找到了我的遗嘱，但它仍然没有给我任何回报：

@Query("select u from SignUp u where u.signUpIdentity.training.id = :trainingId and u.signUpIdentity.user.phoneNumber = :phoneNumber")
SignUp findByTrainingAndUser(@Param("trainingId") long trainingId,
                           @Param("phoneNumber") String phoneNumber);

@RequestMapping(path="/find", method = RequestMethod.POST)
public SignUp readById(@RequestBody SignUpIdentity id) {
      return signUpRepository.findByTrainingAndUser(id.getTraining().getId(), id.getUser().getPhoneNumber());
 }

Answer 1

我认为在您的请求中发送ID会更简单，更容易

{ ＆＃34; id＆＃34;：2 }

并在控制器中更新您的方法以使用ID

进行搜索

Answer 2

尝试更改SignUpRepository以在通用界面中使用Long类型。

public interface SignUpRepository extends PagingAndSortingRepository<SignUp, 
 Long> {

 }

Spring，PagingAndSortingRepository，findOne with @EmbeddedId

2 个答案: