如何从多维对象数组中删除重复项?
在下面的示例中,我有2个项目包含id
值4
(fullname is 'Jodie (Y6Y5)'
)。
我需要修改我的数组,以便没有重复的id
值。
我尝试过循环修复它,我也试过array_unique()
。
有没有人对如何实现这一点有更好的想法?
示例输入数组:
Array
(
[0] => guardian Object
(
[guardians] => Array
(
)
[errors] => Array
(
)
[id] => 4
[pupil_id] => 1
[pupil_id_1] => 2
[pupil_id_2] => 0
[pupil_id_3] => 0
[pupil_id_4] => 0
[school_id] => 1
[title] =>
[firstname] =>
[surname] =>
[fullname] => Jodie (Y6Y5)
[email] => jodie@email.co.uk
[email_2] =>
[telephone] => 0777777777777
[telephone_2] => 07777777777
[username] => jerrys
[password] => password
[active] => 1
[deleted] => 0
[inserted] => 2018-02-06 14:23:02
[updated] => 2018-02-14 14:18:08
[login] => 2018-02-13 15:45:09
[last_login] => 0000-00-00 00:00:00
[email_update_app] => 0
[email_update_app_date] => 0000-00-00 00:00:00
[email_update_web] => 0
[email_update_web_date] => 0000-00-00 00:00:00
[is_wonde] => 0
[wonde_id] =>
[wonde_mis_id] =>
[wonde_upi] =>
[grade_id] => 86
)
[1] => guardian Object
(
[guardians] => Array
(
)
[errors] => Array
(
)
[id] => 3
[pupil_id] => 5
[pupil_id_1] => 2
[pupil_id_2] => 0
[pupil_id_3] => 0
[pupil_id_4] => 0
[school_id] => 1
[title] =>
[firstname] =>
[surname] =>
[fullname] => Karla (Rec Y5)
[email] => karla@email.co.uk
[email_2] => ally@email.com
[telephone] =>
[telephone_2] =>
[username] => rickygutpa
[password] => password
[active] => 1
[deleted] => 0
[inserted] => 2018-02-06 10:33:30
[updated] => 2018-02-14 14:16:21
[login] => 0000-00-00 00:00:00
[last_login] => 0000-00-00 00:00:00
[email_update_app] => 0
[email_update_app_date] => 0000-00-00 00:00:00
[email_update_web] => 0
[email_update_web_date] => 0000-00-00 00:00:00
[is_wonde] => 0
[wonde_id] =>
[wonde_mis_id] =>
[wonde_upi] =>
[grade_id] => 86
)
[2] => guardian Object
(
[guardians] => Array
(
)
[errors] => Array
(
)
[id] => 1
[pupil_id] => 4
[pupil_id_1] => 0
[pupil_id_2] => 0
[pupil_id_3] => 0
[pupil_id_4] => 0
[school_id] => 1
[title] =>
[firstname] =>
[surname] =>
[fullname] => Florence (Y6 2)
[email] => florence@email.co.uk
[email_2] =>
[telephone] => 0777777777777
[telephone_2] =>
[username] => mrslacey
[password] => password
[active] => 1
[deleted] => 0
[inserted] => 2018-02-01 09:47:34
[updated] => 2018-02-14 14:49:32
[login] => 2018-02-05 11:48:54
[last_login] => 0000-00-00 00:00:00
[email_update_app] => 0
[email_update_app_date] => 0000-00-00 00:00:00
[email_update_web] => 0
[email_update_web_date] => 0000-00-00 00:00:00
[is_wonde] => 0
[wonde_id] =>
[wonde_mis_id] =>
[wonde_upi] =>
[grade_id] => 87
)
[3] => guardian Object
(
[guardians] => Array
(
)
[errors] => Array
(
)
[id] => 4
[pupil_id] => 1
[pupil_id_1] => 2
[pupil_id_2] => 0
[pupil_id_3] => 0
[pupil_id_4] => 0
[school_id] => 1
[title] =>
[firstname] =>
[surname] =>
[fullname] => Jodie (Y6Y5)
[email] => jodie@email.co.uk
[email_2] =>
[telephone] => 0777777777777
[telephone_2] => 07777777777
[username] => jerrys
[password] => password
[active] => 1
[deleted] => 0
[inserted] => 2018-02-06 14:23:02
[updated] => 2018-02-14 14:18:08
[login] => 2018-02-13 15:45:09
[last_login] => 0000-00-00 00:00:00
[email_update_app] => 0
[email_update_app_date] => 0000-00-00 00:00:00
[email_update_web] => 0
[email_update_web_date] => 0000-00-00 00:00:00
[is_wonde] => 0
[wonde_id] =>
[wonde_mis_id] =>
[wonde_upi] =>
[grade_id] => 87
)
)
期待结果:
Array
(
[0] => guardian Object
(
[guardians] => Array
(
)
[errors] => Array
(
)
[id] => 4
[pupil_id] => 1
[pupil_id_1] => 2
[pupil_id_2] => 0
[pupil_id_3] => 0
[pupil_id_4] => 0
[school_id] => 1
[title] =>
[firstname] =>
[surname] =>
[fullname] => Jodie (Y6Y5)
[email] => jodie@email.co.uk
[email_2] =>
[telephone] => 0777777777777
[telephone_2] => 07777777777
[username] => jerrys
[password] => password
[active] => 1
[deleted] => 0
[inserted] => 2018-02-06 14:23:02
[updated] => 2018-02-14 14:18:08
[login] => 2018-02-13 15:45:09
[last_login] => 0000-00-00 00:00:00
[email_update_app] => 0
[email_update_app_date] => 0000-00-00 00:00:00
[email_update_web] => 0
[email_update_web_date] => 0000-00-00 00:00:00
[is_wonde] => 0
[wonde_id] =>
[wonde_mis_id] =>
[wonde_upi] =>
[grade_id] => 86
)
[1] => guardian Object
(
[guardians] => Array
(
)
[errors] => Array
(
)
[id] => 3
[pupil_id] => 5
[pupil_id_1] => 2
[pupil_id_2] => 0
[pupil_id_3] => 0
[pupil_id_4] => 0
[school_id] => 1
[title] =>
[firstname] =>
[surname] =>
[fullname] => Karla (Rec Y5)
[email] => karla@email.co.uk
[email_2] => ally@email.com
[telephone] =>
[telephone_2] =>
[username] => rickygutpa
[password] => password
[active] => 1
[deleted] => 0
[inserted] => 2018-02-06 10:33:30
[updated] => 2018-02-14 14:16:21
[login] => 0000-00-00 00:00:00
[last_login] => 0000-00-00 00:00:00
[email_update_app] => 0
[email_update_app_date] => 0000-00-00 00:00:00
[email_update_web] => 0
[email_update_web_date] => 0000-00-00 00:00:00
[is_wonde] => 0
[wonde_id] =>
[wonde_mis_id] =>
[wonde_upi] =>
[grade_id] => 86
)
[2] => guardian Object
(
[guardians] => Array
(
)
[errors] => Array
(
)
[id] => 1
[pupil_id] => 4
[pupil_id_1] => 0
[pupil_id_2] => 0
[pupil_id_3] => 0
[pupil_id_4] => 0
[school_id] => 1
[title] =>
[firstname] =>
[surname] =>
[fullname] => Florence (Y6 2)
[email] => florence@email.co.uk
[email_2] =>
[telephone] => 0777777777777
[telephone_2] =>
[username] => mrslacey
[password] => password
[active] => 1
[deleted] => 0
[inserted] => 2018-02-01 09:47:34
[updated] => 2018-02-14 14:49:32
[login] => 2018-02-05 11:48:54
[last_login] => 0000-00-00 00:00:00
[email_update_app] => 0
[email_update_app_date] => 0000-00-00 00:00:00
[email_update_web] => 0
[email_update_web_date] => 0000-00-00 00:00:00
[is_wonde] => 0
[wonde_id] =>
[wonde_mis_id] =>
[wonde_upi] =>
[grade_id] => 87
)
)
答案 0 :(得分:1)
最佳实践(以及您将在每天的Stackoverflow问题中实现的技术)是分配临时密钥,根据临时密钥覆盖任何预先存在的子代码,然后在最后删除临时密钥。
这避免了必须进行迭代查找。为了最大限度地提高代码效率,请尽量减少迭代函数调用。
方法#1:删除先前重复的事件/保留最后一次出现(Demo)
foreach($guardian->guardians as $subarray){
$result[$subarray->id]=$subarray; // assign temporary keys
}
$guardian->guardians=array_values($result); // re-declare and remove temporary keys (re-index the subarrays)
var_export($guardian);
*或者,这是一个功能风格的单行提供相同的效果:(Demo)
$guardian->guardians=array_values(array_column((array)$guardian->guardians,NULL,'id'));
var_export($guardian);
对于那些不知道的人来说,array_column()
会阻塞对象,所以必须将对象临时转换为数组。
方法#2:删除以后重复的事件/保留第一次出现(Demo)
foreach($guardian->guardians as $subarray){
if(!isset($result[$subarray->id])){
$result[$subarray->id]=$subarray; // only store if first occurrence of id
}
}
$guardian->guardians=array_values($result); // re-index
var_export($guardian);
答案 1 :(得分:0)
我设法通过以下方式获得了有效的答案:
$tempGuardians = array();
foreach($guardian->guardians as $key => $value){
if (in_array($value->id, $tempGuardians)){
unset($guardian->guardians[$key]);
} else {
array_push($tempGuardians, $value->id);
}
}
unset($tempGuardians);
如果有人知道更清洁的方式或更好的方法,我会接受新的方式。
答案 2 :(得分:-1)
答案包含在你的问题中,你已经说过了:array_unique:
$newArray=array_unique($a1);