将列表视图中的项目映射到单击次数

Question

我有一个使用自定义数组适配器填充的ListView。我想获得ListView中每个项目的总点击次数。如何为多个项目映射列表视图项目ID和该项目的点击次数？

Answer 1

使用此代码..完全..硬编码整个代码：p

    HashMap<Integer,Integer> map_positions_and_count = new HashMap<>();

     listView.setOnItemClickListener(new AdapterView.OnItemClickListener() {
        @Override
        public void onItemClick(AdapterView<?> parent, View view, int position, long id) {



            for (int i = 0; i<listView.getAdapter().getCount()-1; i++)
            {

                if (i == position)
                {
                    if (map_positions_and_count .get(position) !=null)
                    {
                        map_positions_and_count .put(position,map_positions_and_count .get(position)+1);


                    }
                    else {
                        map_positions_and_count .put(position,1);


                    }



                }

            }
           // map.put(position,)


        }
    });

您可以在mainActivity中使用它 ..

Answer 2

您可以在活动中尝试此操作，

    ArrayList<Integer> arrayList=new ArrayList<>();//make this as global

    listview.setOnItemClickListener(new AdapterView.OnItemClickListener() {
        @Override
        public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
            if(arrayList.get(position)!=null) {
                int a = arrayList.get(position);
                arrayList.set(position, a+1);
            }
            else
                arrayList.set(position,1);
       }
    });

Answer 3

试试此代码 - ＆gt;

        final HashMap<Integer, Integer> listItemCount = new HashMap<Integer, Integer>();

        //Set an onItemClickListener
        mListView.setOnItemClickListener(new AdapterView.OnItemClickListener() {
            @Override
            public void onItemClick(AdapterView<?> parent, View view, int position, long id) {

                if (listItemCount.containsKey(position)){
                    listItemCount.put(position, listItemCount.get(position)+1);
                }else {
                    listItemCount.put(position, 1);
                }

            }
        });