我正在接收FCM推送通知,但在应用程序处于后台时,在录制系统托盘中发送的通知时未打开该应用程序。
来自后端的有效负载如下所示:
Array(
[registration_ids] => Array
([0] => some value)
[priority] => high
[notification] => Array
(
[body] => Booking Cancelled: Your recent Booking attempt for Sound mix was declined.
[title] => Booking Rejected
[click_action] => USER_BOOKING_REJECTED
[sound] => default
)
[data] => Array
(
[type] => USER_BOOKING_REJECTED
[booking_id] => 331
)
)
我在相关活动的清单中添加了 USER_BOOKING_REJECTED 作为操作。
像这样:
<activity
android:name=".view.activity.HomeActivity"
android:exported="true"
android:screenOrientation="portrait"
android:theme="@style/AppTheme"
android:windowSoftInputMode="adjustPan">
<intent-filter>
<action android:name="USER_BOOKING_APPROVED" />
<action android:name="USER_BOOKING_REJECTED" />
<action android:name="USER_BOOKING_AUTO_REJECTED" />
<action android:name="USER_CANCEL_BOOKING" />
<action android:name="USER_BOOKING_REMINDER" />
<action android:name="USER_INVOICE_EDIT" />
<action android:name="USER_INVOICE_NEW" />
<action android:name="USER_INVOICE_REFUND" />
<action android:name="USER_INVOICE_REMOVE" />
<action android:name="NEW_MESSAGE" />
<action android:name="SP_BOOKING_REMINDER" />
<action android:name="SP_BOOKING_NEW" />
<action android:name="SP_BOOKING_CANCEL" />
<action android:name="SP_INVOICE_PAYMENT" />
<action android:name="SP_NO_FUTURE_SLOT" />
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
<data
android:host="@string/host"
android:pathPrefix="@string/home_path"
android:scheme="http" />
</intent-filter>
</activity>
即使我在系统托盘中收到通知,也会在点按通知时打开该应用。任何帮助?
答案 0 :(得分:1)
您需要在AndroidManifest.xml中为单独的<intent-filter>
单独<action>
。
尝试添加此内容:
<intent-filter>
<action android:name="USER_BOOKING_REJECTED" />
<category android:name="android.intent.category.DEFAULT" />
</intent-filter>
答案 1 :(得分:0)
您需要从后端发送有效负载中的数据而不是通知。然后调用firebase消息服务。
const payload = {
data: {
/*set reuired data over here which you want for generating notification like below*/
message : `${messageSnapshot}`,
vibrate : '1',
sound : '1',
largeIcon : 'large_icon',
smallIcon : 'small_icon'
}
};
return admin.messaging().sendToDevice(deviceToken, payload).then(response => {
// For each message check if there was an error.
const tokensToRemove = [];
response.results.forEach((result, index) => {
const error = result.error;
if (error) {
console.error('Failure sending notification to', deviceToken, error);
// Cleanup the tokens who are not registered anymore.
if (error.code === 'messaging/invalid-registration-token' ||
error.code === 'messaging/registration-token-not-registered') {
tokensToRemove.push(deviceToken);
}
}
});
});
<service
android:name=".services.MyFirebaseMessagingService"
android:enabled="true"
android:exported="true">
<intent-filter>
<action android:name="com.google.firebase.MESSAGING_EVENT" />
</intent-filter>
</service>
public class MyFirebaseMessagingService extends FirebaseMessagingService {
public static String TAG = "MessagingService";
@Override
public void onMessageReceived(RemoteMessage remoteMessage) {
Log.e("MyFirebase","vcdjvbdbv");
if (remoteMessage == null)
return;
// Check if message contains a data payload.
if (remoteMessage.getData().size() > 0) {
Map<String, String> data = remoteMessage.getData();
String message = data.get("message");}}}
答案 2 :(得分:0)
必须升级该库才能使其正常运行。 整整两天一直在挠我的头大声笑。 祝大家编码愉快!
implementation 'com.google.firebase:firebase-messaging:20.2.3'