如何避免在jq中记录重复

Question

我有以下Json：

{
"hits": {
    "hits": [
        {
            "_source": {
                "offers_data": [
                    {
                        "base_price": 198.89, 
                        "shop_id": 2002, 
                        "shop_name": "TheOtherShop"
                    }, 
                    {
                        "base_price": 223, 
                        "shop_id": 2247, 
                        "shop_name": "MainShop"
                    }, 
                    {
                        "base_price": 225, 
                        "shop_id": 2247, 
                        "shop_name": "MainShop"
                    }
                ], 
                "search_result_data": {
                    "identifiers": {
                        "id": 32116
                    }, 
                    "shop": {
                        "id": 2247, 
                        "name": "MainShop" 
                    } 
                }
            }
        }
    ]
}
}

我正在编写以下命令：

jq -c --raw-output '.hits.hits[]|{products_ids: ._source.search_result_data.identifiers.id,
best_shop_id: ._source.search_result_data.shop.id,
best_shop_name: (if ._source.search_result_data.shop.id>0 then ._source.search_result_data.shop.id as $shop_id|._source.offers_data[]|select(.shop_id==$shop_id).shop_name else "" end),
best_offer_base_price: (if ._source.search_result_data.shop.id>0 then ._source.search_result_data.shop.id as $shop_id|._source.offers_data[]|select(.shop_id==$shop_id).base_price else "" end)}'

我得到了这个结果：

{"products_ids":32116,"best_shop_id":2247,"best_shop_name":"MainShop","best_offer_base_price":223}
{"products_ids":32116,"best_shop_id":2247,"best_shop_name":"MainShop","best_offer_base_price":225}
{"products_ids":32116,"best_shop_id":2247,"best_shop_name":"MainShop","best_offer_base_price":223}
{"products_ids":32116,"best_shop_id":2247,"best_shop_name":"MainShop","best_offer_base_price":225}

正如你所看到我得到2个重复：当然我有两个来自MainShop的优惠，所以我得到2个记录是正常的，但如果我也取得基本价格，它会再次复制结果。在我的真实案例中，我得到32条记录而不是2条合法的记录，因为我正在取其他字段。因此，每当我获取字段时，我都希望避免这种额外的重复。

锦上添花将只能获得一条记录，其中Mainshop提供的base_price是最低记录。

由于

Answer 1

结冰

  

... base_price最小的那个。

以下两个对问题的解释都假设我们可以采用具有最小价值的任何可接受项目作为“最小”项目。

原始问题的第一个解释

.hits.hits[]._source
| (.offers_data | min_by(.base_price)) as $min_offers_data
| .search_result_data
| {products_ids: .identifiers.id}
  + ($min_offers_data
    | {best_shop_id: .shop_id,
       best_shop_name: .shop_name,
       best_offer_base_price: .base_price})

输出：

{
  "products_ids": 32116,
  "best_shop_id": 2002,
  "best_shop_name": "TheOtherShop",
  "best_offer_base_price": 198.89
}

第二种解释

将注意力限制在.search_result_data.shop.id：

.hits.hits[]._source
| (.search_result_data.shop.id) as $shop
| (.offers_data | map(select(.shop_id == $shop)) | min_by(.base_price)) as $min_offers_data
| .search_result_data
| {products_ids: .identifiers.id}
  + ($min_offers_data
     | {best_shop_id: .shop_id,
        best_shop_name: .shop_name,
        best_offer_base_price: .base_price})

输出

{
  "products_ids": 32116,
  "best_shop_id": 2247,
  "best_shop_name": "MainShop",
  "best_offer_base_price": 223
}